函数返回主井在python中的位置。
def myPath():
for root,dirs,files in os.walk(dir):
for fn in files:
path = os.path.join(root, fn)
return path
return path
return path
ls /home/bb/C/
a.out main.c simple_write t.c
三个位置";返回";不是我想要的
我想得到结果"C"中的所有文件;
def filesize(path):
for root, dirs, files in os.walk(PATH):
for fn in files:
path = os.path.join(root, fn)
size = os.stat(path).st_size
yield size,path
for size,path in filesize(PATH):
print size,path
但是,如何用以下代码实现上述功能?如何修改?
def find(path):
return [os.path.join(root,fn)
for root,dir,files in os.walk(dirs)
for fn in files]
返回路径的列表,而不仅仅是单个路径:
def find(path):
return [os.path.join(root, fn)
for root, dirs, files in os.walk(path)
for fn in files]
您也可以在内部循环中使用yield
来获得生成器函数,请参阅解释的Python yield关键字。
您想要的是一个生成器:
def myPath(mydir):
for root,dirs,files in os.walk(mydir):
for fn in files:
path = os.path.join(root, fn)
yield path # <----- Instead of return
for path in myPath(some_dir):
print path
如果您只需要/home/bb/C目录列出的,这里有三种方法
import os, glob
def listWithoutDirectories(path):
return [os.path.join(root,fn)
for root,dirs,files in os.walk(mydir)
if(root==path)
for fn in files]
def listWithDirectories(path)
return [os.path.join(path,fn)
for fn in os.listdir(path)]
print listWithoutDirectories('/home/bb/C')
print listWithDirectories('/home/bb/C')
#Or with a glob
print glob.glob('/home/bb/C/*')