我很难在程序中终止我的CIN循环。我的程序使用Linux重定向来读取文件HW07DATA的输入,数据文件看起来像:
100 20 50 100 40 -1
A34F 90 15 50 99 32 -1
N12O 80 15 34 90 22 -1
第一部分是班级的总点,下一行是学生ID编号,其得分是-1终止。
。我的问题:当我运行命令 ./a.out&lt时,我的时循环永远不会终止。HW07DATA ,有人可以查看我的代码并给我一些提示吗?我不想要答案,因为这是作业,我只需要一些指导。谢谢!
#include <iostream>
#include <iomanip>
using namespace std;
const int SENTINEL = -1; //signal to end part of file
const int LTAB = 8; //left tab
const int RTAB = 13; //right tab
int main()
{
cout << "Grant Mercer Assignment 7 Section 1002nn";
cout << setprecision(2) << fixed << showpoint;
cout << left << setw(LTAB) << "ID CODE" <<
right << setw(RTAB) << "POINTS" <<
setw(RTAB) << "PCT" << setw(RTAB) <<
"GRADE" << endl;
double Percentage, //holds students percentage
AvgPercentage;
int Earnedpoints, //earned points for specific student
Totalpoints, //total points possible for all students
AvgPoints, //average points for all students
NumClass; //counts the number of students
Totalpoints = Earnedpoints = //set all vals equal to zero
AvgPoints = AvgPercentage = Percentage = NumClass = 0;
//first and last char for studentID
char Fchar,Lchar, Num1, Num2, Grade;
int TmpVal = 0; //temporary value
cin >> TmpVal;
while(TmpVal != -1) //reading in TOTAL POINTS
{
Totalpoints += TmpVal; //add scores onto each other
cin >> TmpVal; //read in next value
}
while(cin) //WHILE LOOP ISSUE HERE!
{
//read in student initials
cin >> Fchar >> Num1 >> Num2 >> Lchar >> TmpVal;
while(TmpVal != -1)
{
Earnedpoints += TmpVal; //read in points earned
cin >> TmpVal;
}
//calculate percentage
Percentage = ((double)Earnedpoints / Totalpoints) * 100;
AvgPercentage += Percentage;
NumClass++;
if(Percentage >= 90) //determine grade for student
Grade = 'A';
else if(Percentage >= 80 && Percentage < 90)
Grade = 'B';
else if(Percentage >= 70 && Percentage < 80)
Grade = 'C';
else if(Percentage >= 60 && Percentage < 70)
Grade = 'D';
else if(Percentage < 60)
Grade = 'F';
//display information on student
cout << left << Fchar << Num1 << Num2 << setw(LTAB) << Lchar << right << setw(RTAB-3) << Earnedpoints <<
setw(RTAB) << Percentage << setw(RTAB) << Grade << endl;
TmpVal = Earnedpoints = 0;
}
AvgPercentage /= NumClass;
cout << endl << left << setw(LTAB+20) << "Class size: " << right << setw(RTAB) << NumClass << endl;
cout << left << setw(LTAB+20) << "Total points possible: " << right << setw(RTAB) << Totalpoints << endl;
cout << left << setw(LTAB+20) << "Average point total: " << right << setw(RTAB) << AvgPoints << endl;
cout << left << setw(LTAB+20) << "Average percentage: " << right << setw(RTAB) << AvgPercentage << endl;
}
输出继续要求新输入。
您可能会在此找到答案,直到CIN中的cin中读取cin in c
因此,您可以使用getline
通过行读取cin
,然后分析所得的行,例如:
#include <iostream>
#include <sstream>
#include <string>
int main() {
int a, b;
std::string line;
while (std::getline(std::cin, line)) {
std::stringstream stream(line);
stream >> a >> b;
std::cout << "a: " << a << " - b: " << b << std::endl;
}
return 0;
}
编辑:不要忘记检查解析结果并为任何故障进行流状态!
您应该始终检查输入是否成功:
if (std::cin >> TmpVal) {
// do simething with the read value
}
else {
// deal with failed input
}
如果失败,您晚上想检查eof()
,以诱导失败是由于输入结束而导致的。
要处理错误,请查看std::istream::clear()
和std::istream::ignore()
。