将使用zip创建的元组打印到文本文件中

第一次使用python是在今天，所以请原谅我有点垃圾。这是基本代码，我知道它是有效的。

from lxml import html
import lxml
import requests
sourcepage = requests.get('http://www.bbc.co.uk/sport/football/championship/table')
tree = html.fromstring(sourcepage.content)
teamname = tree.xpath('descendant::table[1][@class = "table-stats"]/tbody/tr/td[@class = "team-name"]/a/text()')
position = tree.xpath('descendant::table[1][@class = "table-stats"]/tbody/tr/td[@class = "position"]/span[@class = "position-number"]/text()')
movement = tree.xpath('descendant::table[1][@class = "table-stats"]/tbody/tr/td[@class = "position"]/span[@class="moving-down" or @class="no-movement" or @class="moving-up"]/text()')
goaldiff = tree.xpath('descendant::table[1][@class = "table-stats"]/tbody/tr/td[@class = "goal-difference"]/text()')
points  =  tree.xpath('descendant::table[1][@class = "table-stats"]/tbody/tr/td[@class = "points"]/text()')
combined = zip(teamname,position,movement,goaldiff,points)

它所做的是抓取一个网站，保存为一棵树，并将其变成一个元组(我认为(

使用将表格精细打印到命令行

print("Pos. | Team | P | GD | Ptsn:--:|:--|:--:|:--:|:--:")
for var1,var2,var3,var4,var5 in combined:
    print(var1,"|",var2,var3,"|",var4,"|",var5)

但我在将其打印到文件中时遇到了严重问题。

我尝试了以下方法：

outfile = open('output.txt', 'w')
print>>outfile("Pos. | Team | P | GD | Ptsn:--:|:--|:--:|:--:|:--:")
for var1,var2,var3,var4,var5 in combined:
    print>>outfile(var1,"|",var2,var3,"|",var4,"|",var5)
outfile.close()

此输出一个错误-TypeError:"_io.TextIOWrapper"对象不可调用

with open('output.txt', 'w') as fp:
    fp.write("Pos. | Team | P | GD | Ptsn:--:|:--|:--:|:--:|:--:n")
    for var1,var2,var3,var4,var5 in combined:
        var1s = str(var1)
        print("debug: var1 / var1s set to: ",var1,var1s) #prints nothing (?)
        var2s = str(var2)
        var3s = str(var3)
        var4s = str(var4)
        var5s = str(var5)
        fp.write(var1s+"|"+var2s+var3s+"|"+var4s+"|"+var5s+"n")

这只输出标题行。

(var1a, var2a, var3a, var4a, var5a) = combined
 var1a, var2a, var3a, var4a, var5a = combined
print(var1a)

两人都让我大吃一惊，因为他们都返回了一个ValueError：没有足够的值来解包(预期为5，实际为0(

with open('output.txt', 'w') as fp:
    fp.write('n'.join('{} {} {} {} {}' % x for x in combined))

这会输出一个空白文件，也是如此

outfile = open('outfile.txt', 'w')
for t in combined:
    line = ' '.join(str(x) for x in t)
    outfile.write(line + 'n')
outfile.close()

和

with open('output.txt', 'w') as f:
    for stuff in combined:
        f.write('%s %s %s %s %sn' % stuff)

我花了几个小时在谷歌上搜索，试图找出堆叠式问题的答案，但我还是做得不够，我有点力不从心。

我想将其输出到文件中的原因是，之后的下一步是在输出中运行一些regex，将使用的截断名称转换回它们的正确名称，并在其周围包装一些reddit标记，将它们转换为链接。

>>> z = zip([1,2,3],[4,5,6])
>>> list(z)
[(1, 4), (2, 5), (3, 6)]
>>> list(z)
[]

import sys
sys.stdout=open("test.txt","w")
print("Pos. | Team | P | GD | Ptsn:--:|:--|:--:|:--:|:--:")
for var1,var2,var3,var4,var5 in combined:
    print(var1,"|",var2,var3,"|",var4,"|",var5)
sys.stdout.close()