如何在Java字符串大小写中找到单词Java的敏锐数字

Question

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       String test1 = "java java java. JAVA! ";
       String test2 = "h w !!! ...";
       String word ="java";
       int count = 0;
      String strArray[] = test2.split(" ");
      for(int i=0; i < strArray.length; i++){
            if (word.equals("java")) {
                `enter code here`   
                 count++;
            }            
            System.out.println(strArray[i]);
      }
    System.out.println(count);
    test1.toUpperCase() + test1.toLowerCase().concat;
    count++;
    test1.toLowerCase();
    count++;
    System.out.println(count);

如何在 Java 中返回不区分大小写的出现次数 我会在互联网上拖钓，但没有运气。在 JavaScript 中，我会使用，但在这里我是新手，所以请帮助。所以我需要找到上面建议的 java 不区分大小写的次数

Answer 1

希望这有帮助

String inputString = "java java java. JAVA!";
        int counter = 0;
        Pattern pattern = Pattern.compile("JAVA");
        Matcher match = pattern.matcher(inputString.toUpperCase());
        while (match.find()) {
            counter++;
        }
        System.out.println(counter);

Answer 2

enter code here:
    String regex = "JAVA";
    String input =  "Java java JAVA ss".toUpperCase();
    Pattern p = Pattern.compile(regex);
    Matcher m = p.matcher(input);
    int count = 0;
    List<Integer> index = new ArrayList<>();
    while (m.find()) {
        count++;
        System.out.println("Match number: " + count);
        System.out.println("start: " + m.start());
        System.out.println("end: " + m.end());
        index.add(m.start());
    }
    System.out.println("count: " + count);
    System.out.println("index: " + index.toString());

第一次用这个，希望能帮到你。

Answer 3

为了良好的顺序：

    Pattern pattern = Pattern.compile("java", Pattern.CASE_INSENSITIVE);
    Matcher matcher = pattern.matcher(inputString);
    int count = (int) matcher.results().count();

或短：

    int count = Pattern.compile("java", Pattern.CASE_INSENSITIVE)
            .matcher(inputString).results().count();