我正在开发一个网站,我希望在该网站上访问应用程序中任何地方的状态信息。我尝试了几种实施状态的方法,但是我总是会得到以下错误消息:
元素类型无效:预期一个字符串(用于内置组件(或类/函数(对于复合组件(,但得到:未定义。您可能会忘记从定义的文件中导出组件,或者您可能将默认值混合并命名为导入。
检查SOS
的渲染方法。
这是我的sos-> index.js文件:
import React, { useContext } from 'react';
import axios from 'axios';
import CONST from '../utils/Constants';
import { Grid, Box, Container } from '@material-ui/core';
import { styled } from '@material-ui/styles';
import { Header } from '../Layout';
import ListItem from './ListItem';
import SOSButton from './SOSButton';
import FormPersonType from './FormPersonType';
import FormEmergencyType from './FormEmergencyType';
import StateContext from '../App';
import Context from '../Context';
export default function SOS() {
const { componentType, setComponentType } = useContext(Context);
const timerOn = false;
//'type_of_person',
const ambulance = false;
const fire_service = false;
const police = false;
const car_service = false;
//static contextType = StateContext;
const showSettings = event => {
event.preventDefault();
};
const handleComponentType = e => {
console.log(e);
//this.setState({ componentType: 'type_of_emergency' });
setComponentType('type_of_emergency');
};
const handleEmergencyType = new_emergency_state => {
console.log(new_emergency_state);
// this.setState(new_emergency_state);
};
const onSubmit = e => {
console.log('in OnSubmit');
axios
.post(CONST.URL + 'emergency/create', {
id: 1,
data: this.state //TODO
})
.then(res => {
console.log(res);
console.log(res.data);
})
.catch(err => {
console.log(err);
});
};
let component;
if (componentType == 'type_of_person') {
component = (
<FormPersonType handleComponentType={this.handleComponentType} />
);
} else if (componentType == 'type_of_emergency') {
component = (
<FormEmergencyType
handleComponentType={this.handleComponentType}
handleEmergencyType={this.handleEmergencyType}
emergencyTypes={this.state}
timerStart={this.timerStart}
onSubmit={this.onSubmit}
/>
);
}
return (
<React.Fragment>
<Header title="Send out SOS" />
<StateContext.Provider value="type_of_person" />
<Container component="main" maxWidth="sm">
{component}
</Container>
{/*component = (
<HorizontalNonLinearStepWithError
handleComponentType={this.handleComponentType}
/>*/}
</React.Fragment>
);
}
我真的很感谢您的帮助!
仅供参考,上下文文件定义如下:
import React, { useState } from 'react';
export const Context = React.createContext();
const ContextProvider = props => {
const [componentType, setComponentType] = useState('');
setComponentType = 'type_of_person';
//const [storedNumber, setStoredNumber] = useState('');
//const [functionType, setFunctionType] = useState('');
return (
<Context.Provider
value={{
componentType,
setComponentType
}}
>
{props.children}
</Context.Provider>
);
};
export default ContextProvider;
编辑:我已经根据您的建议更改代码(上面已更新(。但是现在我有以下错误:TypeError:无法读取未定义的
Context
不是 ../Context
文件的默认导出,因此您必须将其导入为:
import { Context } from '../Context';
否则,它正在尝试导入您的Context.Provider
组件。
对于您的文件结构/命名,适当的用法是:
// Main app file (for example)
// Wraps your application in the context provider so you can access it anywhere in MyApp
import ContextProvider from '../Context'
export default () => {
return (
<ContextProvider>
<MyApp />
</ContextProvider>
)
}
// File where you want to use the context
import React, { useContext } from 'react'
import { Context } from '../Context'
export default () => {
const myCtx = useContext(Context)
return (
<div>
Got this value - { myCtx.someValue } - from context
</div>
)
}
and godsakes ...重命名您的上下文文件,提供商以及其中的所有内容。我甚至写了这个。