如何在一个区域上激活函数，在限制区域之外保持活跃

Question

我正在为油漆应用程序编写代码，我想拥有多个刷子。目前唯一的问题是，在此处使用此代码，刷子可以正常工作，但是只有在光标高于实际图标时才起作用。这是代码：

def paintScreen():
    intro = True
    gameDisplay.fill(cyan)
    message_to_screen('Welcome to PyPaint', black, -300, 'large')
    while intro:
        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                pygame.quit()
                quit()
        pygame.draw.rect(gameDisplay, white, (50, 120, displayWidth - 100, displayHeight - 240))
        button('X', 20, 20, 50, 50, red, lightRed, action = 'quit')
        icon(airbrushIcon, white, 50, displayHeight - 101, 51, 51, white, grey, 'airbrush')
        pygame.display.update()
def icon(icon, colour, x, y, width, height, inactiveColour, activeColour, action = None):
        cur = pygame.mouse.get_pos()
        click = pygame.mouse.get_pressed()
        if x + width > cur[0] > x and y + height > cur[1] > y:#if the cursor is over the button
            pygame.draw.rect(gameDisplay, activeColour, (x, y, width, height))
            gameDisplay.blit(icon, (x, y))
            if click[0] == 1 and action != None:
                if action == 'quit':
                    pygame.quit()
                    quit()
                if action == 'pencil':
                    pencil()
                if action == 'airbrush':
                    airbrush()
                if action == 'calligraphy':
                    calligraphy()
                if action == 'erase':
                    pencil()
        else:
            pygame.draw.rect(gameDisplay, inactiveColour, (x, y, width, height))
            gameDisplay.blit(icon, (x, y))
def airbrush(brushSize = 3):
    airbrush = True
    cur = pygame.mouse.get_pos() #cur[0] is x location, cur[1] is y location
    click = pygame.mouse.get_pressed()
    if click[0] == True:
        if cur[0] > 50 < displayWidth - 50 and cur[1] > 120 < displayHeight - 120:
            #the area of the canvas is x(50, width-50) y(120, width-120)
            pygame.draw.circle(gameDisplay, black, (cur[0] + random.randrange(brushSize), cur[1] + random.randrange(brushSize)), random.randrange(1, 5))
        clock.tick(60)

我认识到，仅当光标在图标上方时才调用该问题，但我不知道该移动操作语句或如何更改它们。

Answer 1

您想制作它，因此当用户单击油漆图标时，设置了变量。因此，而不是：

def icon(icon, colour, x, y, width, height, inactiveColour, activeColour, action = None):
        cur = pygame.mouse.get_pos()
        click = pygame.mouse.get_pressed()
        if x + width > cur[0] > x and y + height > cur[1] > y:#if the cursor is over the button
            pygame.draw.rect(gameDisplay, activeColour, (x, y, width, height))
            gameDisplay.blit(icon, (x, y))
            if click[0] == 1 and action != None:
                if action == 'quit':
                    pygame.quit()
                    quit()
                if action == 'pencil':
                    pencil()
                if action == 'airbrush':
                    airbrush()
                if action == 'calligraphy':
                    calligraphy()
                if action == 'erase':
                    pencil()
        else:
            pygame.draw.rect(gameDisplay, inactiveColour, (x, y, width, height))
            gameDisplay.blit(icon, (x, y))

您可以更改此代码，以简单地打开和关闭油漆：

def icon(icon, colour, x, y, width, height, inactiveColour, activeColour, paint_on, action = None):
        cur = pygame.mouse.get_pos()
        click = pygame.mouse.get_pressed()
        if x + width > cur[0] > x and y + height > cur[1] > y and click[0] == 1: # if the cursor is over the button and they clicked
            if paint_on == True:
                paint_on = False
            else:
                paint_on = True
            return paint_on

显然，在您的情况下，由于您有多个工具，因此必须为此功能中的每个工具创建不同的切换，但是我试图保持简单并仅显示单个油漆工具的示例。

现在您有了一个切换，可以在单击图标时更改变量" paint_on"，您可以只检查常规鼠标

def regular_click(colour, x, y, width, height, inactiveColour, activeColour, action = None):
    cur = pygame.mouse.get_pos()
    click = pygame.get_pressed()
    if cur[1] > y and click[0] == 1 and paint_on == True: # if cursor is beneath the tool bar (I'm assuming your tool bar is at the top)
        pygame.draw.rect(gameDisplay, activeColour, (x, y, width, height))

然后将此功能添加到您的主while True循环：

def paintScreen():
    intro = True
    gameDisplay.fill(cyan)
    message_to_screen('Welcome to PyPaint', black, -300, 'large')
    paint_on = False
    while intro:
        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                pygame.quit()
                quit()
        pygame.draw.rect(gameDisplay, white, (50, 120, displayWidth - 100, displayHeight - 240))
        button('X', 20, 20, 50, 50, red, lightRed, action = 'quit')
        paint_on = icon(airbrushIcon, white, 50, displayHeight - 101, 51, 51, white, grey, paint_on, 'airbrush')
        regular_click(paint_on)
        pygame.display.update()

因此，该代码的所有功能如下：

用户单击图标时，它将变量" paint_on"更改为相反（el of Off on或Off），然后在单击任何地方时，它会检查此变量是否已打开，如果Curso不在在工具栏中，如果两个都满足，则绘制。

这就是您的方式。我不能保证此代码可以工作，因为我自己从未使用过Pygame，但我知道这是做这种事情的最佳方法，除非有某种内置功能。