Spring webmvc映射JSP(没有控制器)

Question

我正在尝试使用Spring 3 web-mvc。我有一个简单的页面链接(你知道…<a href="xyz">。

不知道为什么spring mvc不喜欢这样…曾经. .嗯，我的spring配置没有按照我希望的方式工作。

我尝试了DefaultRequestToViewNameTranslator，但没有帮助。我认为这与"Handler"spring dispatcher servlet选择什么有关。但我还不能掌握这些东西。日志输出也没有多大帮助。

有人能帮忙吗?

web.xml

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>classpath:spring/applicationContext.xml</param-value>
</context-param>
<session-config>
    <session-timeout>30</session-timeout>
</session-config> 
<listener>
       <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>
<!-- Reads request input using UTF-8 encoding -->
<filter>
    <filter-name>characterEncodingFilter</filter-name>
    <filter-class>org.springframework.web.filter.CharacterEncodingFilter</filter-class>
    <init-param>
        <param-name>encoding</param-name>
        <param-value>UTF-8</param-value>
    </init-param>
    <init-param>
        <param-name>forceEncoding</param-name>
        <param-value>true</param-value>
    </init-param>
</filter>
<filter-mapping>
    <filter-name>characterEncodingFilter</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>
<!-- Handles all requests into the application -->
<servlet>
    <servlet-name>Spring MVC Dispatcher Servlet</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>
            classpath:spring/appServlet/servlet-context.xml
        </param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
    <servlet-name>Spring MVC Dispatcher Servlet</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

和spring config:

<!-- Scans the classpath of this application for @Components to deploy as beans -->
<context:component-scan base-package="com.mycompany.mvc" />
<!-- Configures the @Controller programming model -->
<mvc:annotation-driven />
<!-- Forwards requests to the "/" resource to the "welcome" view -->
<mvc:view-controller path="/" view-name="index"/>
<!-- Configures Handler Interceptors -->    
<mvc:interceptors>
    <!-- Changes the locale when a 'locale' request parameter is sent; e.g. /?locale=de -->
    <bean class="org.springframework.web.servlet.i18n.LocaleChangeInterceptor" />
</mvc:interceptors>
<!-- Handles HTTP GET requests for /resources/** by efficiently serving up static resources in the ${webappRoot}/resources/ directory -->
<mvc:resources mapping="/css/**" location="/css/" />
<mvc:resources mapping="/js/**" location="/js/" />
<mvc:resources mapping="/images/**" location="/images/" />
<!-- Saves a locale change using a cookie -->
<bean id="localeResolver" class="org.springframework.web.servlet.i18n.CookieLocaleResolver" />
<!-- Application Message Bundle -->
<bean id="messageSource" class="org.springframework.context.support.ReloadableResourceBundleMessageSource">
    <property name="basename" value="/WEB-INF/messages/messages" />
    <property name="cacheSeconds" value="0" />
</bean>
<!-- Automatic resolution of the view names.. Convention over configuration -->
<bean id="viewNameTranslator" class="org.springframework.web.servlet.view.DefaultRequestToViewNameTranslator"/>
<!-- Resolves view names to protected .jsp resources within the /WEB-INF/views directory -->
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
    <property name="prefix" value="/WEB-INF/content/"/>
    <property name="suffix" value=".jsp"/>
</bean>

和jsp，其中定义了链接:

<li><a href="demo/flot">flot integration</a></li>

和日志文件输出:

DEBUG    o.s.web.servlet.DispatcherServlet:693 - DispatcherServlet with name 'Spring MVC Dispatcher Servlet' processing GET request for [/demo/flot]
 WARN         o.s.web.servlet.PageNotFound:947 - No mapping found for HTTP request with URI [/demo/flot] in DispatcherServlet with name 'Spring MVC Dispatcher Servlet'
DEBUG    o.s.web.servlet.DispatcherServlet:674 - Successfully completed request

Answer 1

控制器应该处理用户的请求，在你的情况下没有映射到这个URL的控制器。当找到控制器时，它执行一些逻辑并返回视图名，视图名将用于表示服务器的响应。因此，视图名转换器只能在控制器之后调用，并且只能用于推导特定JSP文件的完整路径。

尝试添加

<mvc:view-controller path="demo/flot" view-name="demo/flot"/>

(另外，您可能会尝试省略view-name属性，但我不确定)

Answer 2

目前…后工作. .虽然属性/**可能是一个问题，我以后当我添加控制器也。

但是我可以定制。jsp文件url

<bean id="handlerMapping"
    class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
    <property name="mappings">
        <props>
            <prop key="/**">urlFilenameViewController</prop>
        </props>
    </property>
</bean>
<bean id="urlFilenameViewController" class="org.springframework.web.servlet.mvc.UrlFilenameViewController" /> 

Answer 3

使用spring-webmvc 3.0.6。RELEASE this for me:

<!-- Enables the Spring MVC @Controller programming model -->
<annotation-driven />
<view-controller path="secure/*" view-name="secure/index"/>
<view-controller path="secure/extreme/*" view-name="secure/extreme/index"/>
<!-- Resolves views selected for rendering by @Controllers to .jsp resources 
    in the /WEB-INF/views directory -->
<beans:bean
    class="org.springframework.web.servlet.view.InternalResourceViewResolver">
    <beans:property name="prefix" value="/WEB-INF/views/" />
    <beans:property name="suffix" value=".jsp" />
</beans:bean>

用@Controller和@RequestMapping注释的bean在适当的url上被调用，任何像secure/*和secure/extreme/*这样的url分别由WEB-INF/views/secure/index.jsp和WEB-INF/views/secure/extreme/index.jsp处理

Answer 4

我正在使用spring web 3.2.1，我只有内部解析器和基于注释的配置。默认情况下，无需使用控制器即可访问jsp文件视图，也就是说，没有在映射控制器方法的返回值中编码到任何控制器中。

Answer 5

放置

<bean id="messageSource" class="org.springframework.context.support.ReloadableResourceBundleMessageSource"> <property name="basename" value="/WEB-INF/messages/messages" /> <property name="cacheSeconds" value="0" /> </bean>

application-context.xml中的

为我解决了这个问题。如果我们将这些东西放入servlet.xml中，没有控制器的视图(请求映射)将无法加载。我试着把这些东西放在application-context.xml中，它对我很有效。谢谢! !

Answer 6

在3.1版本之后，有WebMvcConfigurerAdapter，所以你可以像这样把映射放在配置中:

@Configuration
@EnableWebMvc
public class WebConfig extends WebMvcConfigurerAdapter {
  @Override
  public void addViewControllers(ViewControllerRegistry registry) {
    registry.addViewController("/").setViewName("/index");
  } 
}