我试图创建一个对象的实例,也有类组成到它:
[DataContract(Name = "share", Namespace = "")]
public class RequestShareDocument
{
[DataMember(Order = 0)]
public string profile_name { get; set; }
[DataMember(Order = 1)]
public List<RequestSigner> signers {get; set;}
[DataMember(Order = 2)]
public bool createcopy { get; set; }
}
[DataContract(Name = "signer", Namespace = "")]
public class RequestSigner
{
[DataMember(Order = 0)]
public string email { get; set; }
[DataMember(Order = 1)]
public string order { get; set; }
[DataMember(Order = 2)]
public string reminder { get; set; }
[DataMember(Order = 3)]
public RequestSignerPermissions permissions { get; set; }
[DataMember(Order = 4)]
public string signature_field { get; set; }
}
[DataContract(Name = "permissions", Namespace = "")]
public class RequestSignerPermissions
{
[DataMember(Order = 0)]
public bool save_locally {get;set;}
[DataMember(Order = 1)]
public string open_password { get; set; }
[DataMember(Order = 2)]
public DateTime accessible_after { get; set; }
[DataMember(Order = 3)]
public DateTime accessible_before { get; set; }
[DataMember(Order = 4)]
public string certify_level { get; set; }
}
我需要创建一个类的实例并序列化到XML,但我不知道如何做到这一点?
我能够创建一个类的实例,但当涉及到List<T>
属性时,我无法创建它。我已经试过了:
if (typeof(IEnumerable).IsAssignableFrom(item.PropertyType))
IList list = (IList)Activator.CreateInstance(typeof(List<>));
…为了序列化,我使用:
XmlSerializer mySerializer = new XmlSerializer(typeof(T), new
XmlRootAttribute(RootElementName));
StringWriter sww = new StringWriter();
XmlWriter writer = XmlWriter.Create(sww, new XmlWriterSettings()
{ OmitXmlDeclaration = true, Indent = true });
mySerializer.Serialize(writer, item);
writer.Close();
sww.Close();
问题是当我循环所有属性并到达List
时,我不知道如何创建List
的实例。这是可能的还是我做错了什么?
如果我理解正确的话,这段代码就是您想要的:
public static object InitializeTarget(Type type)
{
object target = CreateObject(type);
foreach (PropertyInfo propertyInfo in type.GetProperties())
{
if (propertyInfo.PropertyType.IsClass && propertyInfo.CanWrite
&& propertyInfo.PropertyType != typeof(string)
&& (propertyInfo.IsDefined(typeof(DataMemberAttribute), true)))
propertyInfo.SetValue(target, InitializeTarget(propertyInfo.PropertyType), null);
}
return target;
}
public static object CreateObject(Type type)
{
if (typeof(IList).IsAssignableFrom(type) && type.IsGenericType)
{
Type[] genericArguments = type.GetGenericArguments();
if (genericArguments.Length == 1)
{
var list = (IList)Activator.CreateInstance(type);
//Adding default value
list.Add(CreateObject(genericArguments[0]));
return list;
}
}
//If the object is only to serialize, you can use it
return FormatterServices.GetUninitializedObject(type);
//or
// return Activator.CreateInstance(type);
}