单击"批准"按钮时禁用"拒绝"按钮的最佳方法是什么?我有{{some}}存储批准或拒绝值的值。
<a href="{% url 'hrfinance:edit' id=item.id status='a' %}"><button>Approve</button></a>
<a href="{% url 'hrfinance:edit' id=item.id status='d' %}"><button>Deny</button></a>
html文件
{% if some %}
<table id="example" class="display" cellspacing="0" width="100%" border="1.5px">
<tr align="center">
<th> Student ID </th>
<th> Student Name </th>
<th> Start Date </th>
<th> End Date </th>
<th> Action </th>
<th> Status </th>
</tr>
{% for item in query_results %}
<tr align="center">
<td> {{item.studentID}} </td>
<td> {{item.studentName}} </td>
<td> {{item.startDate|date:'d-m-Y'}} </td>
<td> {{item.endDate|date:'d-m-Y'}} </td>
<td><a href="{% url 'hrfinance:edit' id=item.id status='a' %}"><button>Approve</button></a> <a href="{% url 'hrfinance:edit' id=item.id status='d' %}"><button {% if some == 'approve' %} disabled{% endif %}>Deny</button></a></td>
<td>
{% if item.status %}
{{item.status}}
{% else %}
Pending
{% endif %}
</td>
</tr>
{% endfor %}
</table>
{% else %}
{{some}}从这里
views.py
def superltimesheet(request):
query_results = Timesheet.objects.all()
data={'query_results':query_results, 'some':'some'}
return render(request, 'hrfinance/supervisor_list_timesheet.html', data)
使用if
标签:
<button{% if some == 'deny' %} disabled{% endif %}>Approve</button>
我不确定您在问什么,但是您可以执行
之类的语句{% if some == 'approve' %}
<a href="{% url 'hrfinance:edit' id=item.id status='d' %}"><button>Deny</button></a>
{% else %}
<a href="{% url 'hrfinance:edit' id=item.id status='a'%}"><button>Approve</button></a>
{% endif %}
或:
{% if some == 'approve' %}
<button>Deny</button>
{% else %}
告诉我这是否有效或我误解了