显示/隐藏多个 div 取决于屏幕角度 2

Question

我想使用一些按钮来显示/隐藏多个div

该页面最初将显示所有div。 当小屏幕我隐藏所有div时，然后分开按钮以显示特定div，同时隐藏其余部分。

任何帮助将不胜感激。

<div class="buttons">
<a class="button" id="showdiv1">Div 1</a>
<a class="button" id="showdiv2">Div 2</a>
<a class="button" id="showdiv3">Div 3</a>
</div>

<div class="row">
  <div class="col-xlg-4 col-xl-5 col-lg-12 col-sm-12 col-xs-12 hidden-sm-down">
  </div>
   <div class="col-xlg-4 col-xl-5 col-lg-12 col-sm-12 col-xs-12 hidden-sm-down">
  </div>
   <div class="col-xlg-4 col-xl-5 col-lg-12 col-sm-12 col-xs-12 hidden-sm-down">
  </div>
</div>

Answer 1

将@HostListener与 resize 事件一起使用来确定视区的宽度。然后在组件中设置具有此值的赋值属性，然后可以将其提供给 HTML 模板中的ngIf*。

import { Component, HostListener, AfterViewInit } from '@angular/core';
@Component()
export class AppComponent { 
  windowWidth: number = window.innerWidth;
  //initial values, The window object may still be undefined during this hook, let me know if that's the case and we'll figure out a better hook for the initial value
  ngAfterViewInit() {
      this.windowWidth = window.innerWidth;
  }
  //if screen size changes it'll update
  @HostListener('window:resize', ['$event'])
  resize(event) {
      this.windowWidth = window.innerWidth;
  }
}

<!-- Then any HTML element you wish to toggle apply the *ngIf directive as so: -->
<div *ngIf*="windowWidth > 800">content</div>