这是我的第一个郎,所以我在这个领域是新手。请帮帮我。我正在做作业,在编译过程中收到了一个错误:"不兼容类型"。我以前上过的第一堂课,它很管用。员工阶级我不应该再碰了。
class Employee{
private String firstName; // First name of employee
private String lastName; // Last name of employee
private String id; // Personal id number of employee
private String emNum; // Employee number
static int counter = 0; // The counter variable will keep track the number of employee
public Employee(String firstName, String lastName, String id)
{
this.firstName = firstName;
this.lastName = lastName;
this.id = id;
emNum = "EMPTY";
counter++;
}
public void setFirstName(String firstName)
{
this.firstName = firstName;
}
public String getFirstName()
{
return firstName;
}
public void setLastName(String lastName)
{
this.lastName = lastName;
}
public String getLastName()
{
return lastName;
}
public void setid(String id)
{
this.id = id;
}
public String getid()
{
return id;
}
public void setEmNum(String emNum)
{
this.emNum = emNum;
}
public String getEmNum()
{
return emNum;
}
public static int getNumberOfEmployees()
{
return counter;
}
public String toString()
{
if(emNum == "EMPTY"){
setEmNum("Employee number:No employee number has been assigned yet!");
}
else
return emNum;
return ("ntFirst Name: " + getFirstName() + " " +"Last Name: " + getLastName()
+ " " + "ntId number: " + getid() + " " + "ntEmployee number: " + getEmNum() );
}
}
在A1Q2课上,我遇到了问题。在循环中,我想在一个数组中创建这些员工的列表。它显示了"找不到符号"的错误。事实上,我看到类型r不同,所以它无法将String类型写入Employee,但我不知道如何修复它。
必填项:员工
已找到:java.lang.String
class TestA1Q2
{
public static void main(String[] args)
{
String[] firstNames= {"Fred","John","Amir", "James","Bob","Jay","Amber"};
String[] lastNames = {"Bond","Kates","Memar", "White","Marley","Brown","Nogofski"};
String[] idNumbers = {"R111111","A222222","AB11111", "KR22121","V311133","L242434","P102432"};
String[] employeeNum = {"1111","2222","3333", "4444","5555","6666","7777"};
Employee[] list = new Employee[firstNames.length];
list = listOfEmployees(firstNames,lastNames,idNumbers); // create the list of employees in one array
System.out.println(list);
System.out.println(Employee.getNumberOfEmployees());
}
// DON`T TOUCH ABOVE PART
static Employee[] listOfEmployees(String[] firstNames, String[] lastNames, String[] idNumbers)
{
Employee[] employee = new Employee[firstNames.length];
for (int i = 0; i < firstNames.length; i++){
employee[i] = firstNames[i] + lastNames[i] + idNumbers[i];
}
return employee;
}
}
您正在联系字符串,并试图将它们存储到Employee数组中。您必须使用firstName、lastName和ID创建一个新的employee对象,然后将引用存储在employee数组中。
Employee[] employee = new Employee[firstNames.length];
for (int i = 0; i < firstNames.length; i++){
employee[i] = new Employee(firstNames[i],lastNames[i],idNumbers[i]);
}
return employee;
如果有效的话,请回复。
我不相信一个列表可以是三维的(包含名字、姓氏、idNumbers(。如果你创建了三个列表,listFirstNames、listLastNames、listIDNumbers,同时填充它们,可能会起作用:
Employee[] employee = new Employee[firstNames.length];
for (int i = 0; i < firstNames.length; i++){
listFirstNames[i] = firstNames[i];
listLastNames[i] = lastnames[i];
listIDNumbers[i] = idNumbers[i];
}
}