我是拉拉维尔的新手,所以这可能是我的错误。使用 laravel与 tymondesigns/jwt-auth 以验证用户。我正在观看本教程 使用 Laravel 完成 JWT-AUTH api,并遵循每一步,tymon 软件包安装和登录用户。但是我收到此错误。我在下面发布了代码,告诉我您是否需要来自任何其他文件的更多代码。
EloquentUserProvider 中的 ErrorException.php第 120 行:参数 1 已传递 to Illuminate\Auth\EloquentUserProvider::validateCredentials(( 必须是 Illuminate\Contracts\Auth\Authenticatable的实例,实例 应用\用户给定
这是我的用户模型:
<?php
namespace App;
use IlluminateDatabaseEloquentModel;
class User extends Model
{
protected $hidden = ["password"];
protected $fillable = [
"id",
"name",
"password",
"mobile_number",
"gender",
"age",
"company_name",
"profile_image",
"email"
];
}
?>
这是我的ApiAuthController.php
use JWTAuth;
use IlluminateHttpRequest;
use TymonJWTAuthExceptionsJWTException;
class ApiAuthController extends Controller
{
public function authenticate(){
$credentaials = request()->only('email', 'password');
print_r($credentaials);
try {
$token = JWTAuth::attempt($credentaials);
if(!$token){
return response()->json(['error'=>'invalid credentaials'], 401);
}
} catch (JWTException $e) {
return response()->json(['error'=>'something went wrong'], 500);
}
return response()->json(['token'=>$token], 200);
}
}
我的用户控制器中的用户存储功能:
public function store(Request $request)
{
$payload = json_decode($request->payload, true);
$validator = Validator::make($payload, $this->rules);
if ($validator->passes()) {
$user = (new User())->fill($payload);
if($user->save()){
$response = [
"msg" => "User created",
"link" => "/api/users/" . $user->id
];
return response()->json($response, 200);
}
$response = [
"msg" => "An error occured"
];
return response()->json($response, 404);
}
else {
return response()->json($validator->messages(), 404);
}
}
在存储用户请求时,有效负载是键,值是json对象,下面给出了小示例对象:
payload={
"name": "Alexa",
"email": "alexa@gmail.com",
"password":"12345",
"gender": "Male",
"age": 24
}
将其添加到您的模型中
use IlluminateFoundationAuthUser as Authenticatable;
并更改此行
class User extends Authenticatable
编辑:看起来您正在以明文形式存储密码。将其添加到您的用户模型中。
public function setPasswordAttribute($value)
{
$this->attributes['password'] = bcrypt($value);
}