随机进行两个连续的数据块

Question

i有数据文件(PHP(，其中24个数据块，如下所示。

//ts1
$P[] = [0];
$S[] = [[1,95.8172406762736],[2,104.97526726371],[3,112.03839938973],[4,101.70457396977],];
$F[] = [];
$FB[] = [];
//ts2
$P[] = [0];
$S[] = [[1,103.190939795922],[2,105.297198378469],[3,105.829786652111]];
$F[] = [];
$FB[] = [];
//ts3
$P[] = [0];
$S[] = [[1,107.285278217373],[2,103.557795069809],[3,105.686758569246],[4,103.748341353355]];
$F[] = [];
$FB[] = [];

我需要洗牌前12个街区，然后将块13-24散步。我所拥有的代码似乎不起作用，因为它仍然一次将所有24个块洗牌。我不确定应该如何写。

// DATA INITIALISATION
// - Reads all data sets from server
// - Generates list of objects
// - Randomises list of objects
function DataInit1()
{
    SeriesList = [];
    CurrentGraph.Series = 0;
    // load all the data sets from server
    $.getJSON("datademo.php",
        function(Data1)
        {
            for(var i=0; i<Data1.length; i+=4)
            {
                var P = Data1[i+0];
                var S = Data1[i+1];
                var F = Data1[i+2];
                var FB = Data1[i+3];
                var NewSeries = new SeriesClass(P,S,F,FB);
                NewSeries.SeriesNumber = (i/4)+1;
                SeriesList.push(NewSeries);
            }
        }
    );
// shuffle each of the series lists to a random order
    s1 = SeriesList.length/2;
    s2 = SeriesList.length;
    for(var i=0; i<s1; i++) 
    {
           var j = Math.floor(Math.random() * (i+1));
           var x = SeriesList[i];
           SeriesList[i] = SeriesList[j];
           SeriesList[j] = x;
         }
    for(var i=s1; i<s2; i++) 
    {
           var j = Math.floor(Math.random() * (i+1));
           var x = SeriesList[i];
           SeriesList[i] = SeriesList[j];
           SeriesList[j] = x;
         }
    }

编辑：我现在将其更改为以下内容(不是很漂亮，但我没有时间整理它(。现在它随机化系列1-12，但是序列13-24现在不是随机的。我不经常编码，我看不出为什么它会在第一个位置起作用，而不是第二位。

// shuffle the series list to a random order
    for(var i=SeriesList.length-13; i>0; i--) 
    {
        var j = Math.floor(Math.random() * (i+1));
        var x = SeriesList[i];
        SeriesList[i] = SeriesList[j];
        SeriesList[j] = x;
    }
        for(var i={from: 12, to: 23}; i>0; i--) 
    {
        var j = Math.floor(Math.random() * (i+1));
        var x = SeriesList[i];
        SeriesList[i] = SeriesList[j];
        SeriesList[j] = x;
    }

Answer 1

我认为最简单的方法是将其分成两个阵列，将它们分开洗牌，然后将它们推回在一起。我已经从这个问题中使用了混音方法：如何将数组洗牌？以及如何使用另一个数组扩展现有的JavaScript数组，而无需创建新数组？

请参阅https://jsfiddle.net/u25ta64x/1/

var SeriesList = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26];
var firstHalf = SeriesList.slice(0,13);
var secondHalf = SeriesList.slice(13,26);
function shuffle(a) {
    var j, x, i;
    for (i = a.length; i; i--) {
        j = Math.floor(Math.random() * i);
        x = a[i - 1];
        a[i - 1] = a[j];
        a[j] = x;
    }
}
shuffle(firstHalf);
shuffle(secondHalf)
var shuffledList = firstHalf;
Array.prototype.push.apply(shuffledList, secondHalf);
console.log(shuffledList);