我正在使用presto,并尝试从嵌套的JSON结构中从'source''='dd'中提取所有'id'。
{
"results": [
{
"docs": [
{
"id": "apple1",
"source": "dd"
},
{
"id": "apple2",
"source": "aa"
},
{
"id": "apple3",
"source": "dd"
}
],
"group": 99806
}
]
}
期望将ID [Apple1,Apple3]提取到Presto的一列中我想知道在Presto查询中实现这一目标的正确方法是什么?
如果您的数据具有常规结构,如您发布的示例,您可以将解析值作为JSON的组合,将其施放为结构化的SQL类型(array/map/ap/row/row(以及使用数组处理功能来过滤,转换和提取所需的元素:
WITH data(value) AS (VALUES '{
"results": [
{
"docs": [
{
"id": "apple1",
"source": "dd"
},
{
"id": "apple2",
"source": "aa"
},
{
"id": "apple3",
"source": "dd"
}
],
"group": 99806
}
]
}'),
parsed(value) AS (
SELECT cast(json_parse(value) AS row(results array(row(docs array(row(id varchar, source varchar)), "group" bigint))))
FROM data
)
SELECT
transform( -- extract the id from the resulting docs
filter( -- filter docs with source = 'dd'
flatten( -- flatten all docs arrays into a single doc array
transform(value.results, r -> r.docs) -- extract the docs arrays from the result array
),
doc -> doc.source = 'dd'),
doc -> doc.id)
FROM parsed
上面的查询产生:
_col0
------------------
[apple1, apple3]
(1 row)