if message.content.lower().startswith('!kick') and (roleLFJob in message.author.roles or roleLFAba in message.author.roles):
await client.delete_message(message)
serverchannel = '405090256124248065'
messageParsed = message.content.split()
kick = messageParsed[0]
mention = messageParsed[1]
msg = messageParsed[2:]
for member in message.mentions:
await client.kick(member)
await client.send_message(discord.Object(id=serverchannel), '{0} was kicked by {1}, with reason:"**'.format(member.mention, message.author.mention) + msg + '**"')
当我在不和谐中编写此命令时:
!kick @(member.mention) reason, reason and reason
发生此错误:
Ignoring exception in on_message Traceback (most recent call last):
File "C:UserssenukAppDataLocalProgramsPythonPython35libsite-packagesdiscordclient.py", line 307, in _run_event
yield from getattr(self, event)(*args, **kwargs)
File "overmind.py", line 128, in on_message
await client.send_message(discord.Object(id=serverchannel), '{0} was kicked by {1} with reason:"**'.format(member.mention, message.author.mention) + msg + '**"')
TypeError: Can't convert 'list' object to str implicitly
既然你输入了这个:
!kick @(member.mention) reason, reason and reason
然后,当您拆分整个内容时:
messageParsed = message.content.split()
kick = messageParsed[0]
mention = messageParsed[1]
msg = messageParsed[2:]
结果将是:
kick = "!kick"
mention = "@(member.mention)"
msg = ["reason,", "reason", "and", "reason"]
在代码的最后一行,您尝试将两个字符串与 msg (list( 连接起来。这是不可能的。
您可能希望msg
为字符串,因此您应该使用:
msg = " ".join(messageParsed[2:])
将msg
重新制作回其原始形式:
msg = "reason, reason and reason"