AngularJS - 仅当一个字段大于另一个字段时才验证

Question

>我有两个输入字段，一个是From Year，另一个是To Year。仅当表单的提交按钮大于From Year值时，我才必须验证To Year。

这是从年份开始的代码：

<div class="col-md-6 no-pad-right">
<label>Tenure From Year</label>
<input name="tenure_from_year" ng-model="joinFormData.tenureFromYear" name="tenure_from_year" class="form-control" placeholder="2014" type="text" ng-required="joinFormData.memberType == 'alumni'" ng-maxlength="4" ng-pattern="/(?:(?:19|20)[0-9]{2})/">
<span ng-show="joinForm.tenure_from_year.$error.pattern || joinForm.tenure_from_year.$error.maxlength">
<span class="red-color">Enter correct year!</span>
</span>
</div>

这是 to year 的代码：

<div class="col-md-6 no-pad-right">
<label>Tenure To Year</label>
<input name="tenure_to_year" ng-model="joinFormData.tenureToYear" name="tenure_to_year" class="form-control" placeholder="2014" type="text" ng-required="joinFormData.memberType == 'alumni'" ng-maxlength="4" ng-pattern="/(?:(?:19|20)[0-9]{2})/">
<span ng-show="joinForm.tenure_to_year.$error.pattern || joinForm.tenure_to_year.$error.maxlength">
<span class="red-color">Enter correct year! </span>
</span>
</div>

如果表单无效，则禁用提交按钮

<button type="submit" class="btn btn-default btn-save-custom"  ng-click="joinLeap()" ng-disabled="joinForm.$invalid" >Submit</button>

那么我如何验证开始年份和结束年份字段，以便在年份有效时启用提交按钮。

Answer 1

您可以使用watch .

$scope.validate = false;
$scope.$watch('joinFormData.tenureFromYear', function (newVal, oldVal) {
if (newVal > oldVal) {
$scope.validate = true;
} else {
$scope.validate = false;
}
});

Answer 2

比较您在ng-click中提到的方法joinLeap()ng-model字段中的字段

$scope.dateValidation = false;
$scope.joinLeap = function (joinFormData) {
if (joinFormData.tenureToYear > joinFormData.tenureFromYear) {
$scope.dateValidation = true;
} else {
$scope.dateValidation = false;
}
}

通过ng-click方法传递参数

<button type="submit" class="btn btn-default btn-save-custom"  ng-click="joinLeap(joinFormData)" ng-disabled="joinForm.$invalid || !dateValidation" >Submit</button>

我想这会对你有所帮助。 根据要求为日期验证设置真、假值。