我需要获取日期范围内的星期一列表。
例如:
# selected date range
date_range = ['2019-02-25', '2019-03-25']
# desired output:
mondays = ['2019-02-25', '2019-03-04', '2019-03-11', '2019-03-18', '2019-03-25']
# selected date range
date_range = ['2019-02-25', '2019-03-20']
# desired output
mondays = ['2019-02-25', '2019-03-04', '2019-03-11', '2019-03-18']
开始日期始终是星期一。
有谁知道我如何使用python日期时间生成星期一列表?
这是使用weekday((的一种方法。
前任:
import datetime
def get_mondays(date_start, date_end):
date_start = datetime.datetime.strptime(date_start, "%Y-%m-%d")
date_end = datetime.datetime.strptime(date_end, "%Y-%m-%d")
result = []
while date_start <= date_end:
if date_start.weekday() == 0: #0 == Monday
result.append(date_start.strftime("%Y-%m-%d"))
date_start += datetime.timedelta(days=1)
return result
print(get_mondays('2019-02-25', '2019-03-25'))
print(get_mondays('2019-02-25', '2019-03-20'))
输出:
['2019-02-25', '2019-03-04', '2019-03-11', '2019-03-18', '2019-03-25']
['2019-02-25', '2019-03-04', '2019-03-11', '2019-03-18']
如果您可以使用第三方模块dateutil
:
from dateutil import rrule, parser
def case_of_the_mondays(start,end):
mondays = list(rrule.rrule(rrule.WEEKLY,
dtstart=parser.parse(start),
until=parser.parse(end)))
return mondays
结果:
In [22]: case_of_the_mondays('2019-02-25','2019-03-25')
Out[22]:
[datetime.datetime(2019, 2, 25, 0, 0),
datetime.datetime(2019, 3, 4, 0, 0),
datetime.datetime(2019, 3, 11, 0, 0),
datetime.datetime(2019, 3, 18, 0, 0),
datetime.datetime(2019, 3, 25, 0, 0)]