在Java中排序一个2d字符串数组

Question

我用Java为一个项目创建了一个2d数组，该项目读取文件、处理数据并将其打印出来。我遇到的唯一问题是试图按字母顺序对2d数组进行排序。

这是一个文件输入的例子:

2011 Regular Season
Boston 162 5710 875 1600 352 35 203
NY_Yankees 162 5518 867 1452 267 33 222
Texas 162 5659 855 1599 310 32 210
Detroit 162 5563 787 1540 297 34 169
St.Louis 162 5532 762 1513 308 22 162
Toronto 162 5559 743 1384 285 34 186
Cincinnati 162 5612 735 1438 264 19 183
Colorado 162 5544 735 1429 274 40 163
Arizona 162 5421 731 1357 293 37 172
Kansas_City 162 5672 730 1560 325 41 129

下面是输出的示例:

2011 Regular Season
====================
Boston:     .280 .461
NY_Yankees: .263 .444
Texas:      .283 .460
Detroit:    .277 .434
St.Louis:   .273 .425
Toronto:    .249 .413
Cincinnati: .256 .408
Colorado:   .258 .410
Arizona:    .250 .413
Kansas_City:.275 .415
====================
Big Ten Av: .266 .428

我的目标是让球队的名字按字母顺序排序。我尝试过使用Array.sort()方法以及使用比较器，但没有任何效果。我将包括工作代码，我现在和任何帮助将是伟大的!

package problem_1;
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
import java.text.DecimalFormat;
import java.util.Arrays;
import java.util.Comparator;
public class sluggers2 {
static String specificstat[][] = new String[1000][1000]; //Create a 2-dimensional array with limits of 1000
static DecimalFormat df = new DecimalFormat(".###");//Variable to round the integers to 3 decimal places
public static void main(String args[]) { //Main method
    execute(); //Call on the function "execute" and execute it
    baseballstats(1);
}
public static String[][] execute() {
    int line = 0;
    try {
        BufferedReader in = new BufferedReader(new FileReader("stuff/input_sluggers.txt"));
        String str;
        while ((str = in.readLine()) != null) {
            if (str.trim().length() == 0) {
                continue; // Skip blank lines
            }
            specificstat[line] = str.split(" ");
            line++;
        }
        in.close();
    } catch (IOException e) {
        System.out.println("Can not open or write to the file.");
    }
    return specificstat;
}
public static void baseballstats(int teamnumber) {
    double batting_average, slugging_average = batting_average = 0;
            //Arrays.sort(specificstat[0]);
            //Tried sorting the first dimension but it didn't work
    System.out.println(specificstat[0][0] + " " + specificstat[0][1] + " " + specificstat[0][2]);
    System.out.println("====================");
    while (teamnumber <= 10) {
        double B = Integer.parseInt(specificstat[teamnumber][5]);
        double C = Integer.parseInt(specificstat[teamnumber][6]);
        double D = Integer.parseInt(specificstat[teamnumber][7]);
        double A = Integer.parseInt(specificstat[teamnumber][4]) - (B + C + D);
        double slug_avg = ((A + 2*B + 3*C + 4*D) / Integer.parseInt(specificstat[teamnumber][2]));
        double y = Integer.parseInt(specificstat[teamnumber][4]), z = Integer.parseInt(specificstat[teamnumber][2]), bat_avg = y / z;
        slugging_average = slugging_average + slug_avg;
        batting_average = batting_average + bat_avg;
        double hits = Integer.parseInt(specificstat[teamnumber][4]);
        double at_bats = Integer.parseInt(specificstat[teamnumber][2]);
        String batting = df.format(hits / at_bats), slugging = df.format(slug_avg);
        if (slugging.length() == 3)
            slugging = slugging + "0";
        if (batting.length() == 3)
            batting = batting + "0";
        System.out.println(specificstat[teamnumber][0] + ":  " +  "t" + batting + " " + slugging);
        teamnumber++;
    }
    String big_ten_av = "t" + df.format(batting_average / 10) + " "+ df.format(slugging_average / 10);
    System.out.println("====================");
    System.out.print("Big Ten Av: "); System.out.print(big_ten_av);
}
}

我对编码比较陌生，所以任何帮助都会非常感激。

Answer 1

你需要这样做:

Arrays.sort( specificstat, new Comparator<String[]> {
    public int compare( String[] s1, String[] s2 ) {
        return s1[0].compareTo(s2[0]);
    }
} );

这基本上是说通过比较每个内部数组的第一个元素来对specificstat的内部数组进行排序。

Answer 2

对于Lucas的另一种解决方案是完全消除2d数组，并使用某种类的数组，例如:

class TeamRecord implements Comparable {
  public String teamName;
  public ArrayList<Integer> stats;
  int compareTo(TeamRecord other) {
    return teamName.compareTo(other.teamName);    
  }
}

并更改你的:

static String specificstat[][] = new String[1000][1000];

:

static TeamRecord specificstat[] = new TeamRecord[1000];

然后Array.sort(specificstat)将根据teamName排序。

这种方法的优势在于它让你的数据更清晰，因为团队名称与统计数据是完全不同的东西;这里的类型使这一点一目了然。

我省略了将填充该数据类型的数组的代码，但我认为您可以找出它