刷新动态创建的表

Question

我想在将值存储到数据库中后刷新动态创建的表。我尝试如下：

  $('#caseTbl tr').each(function(){
        $(this).droppable({
            activeClass: "ui-state-default",
            hoverClass: "ui-drop-hover",
            accept: "#serviceTechs tr",
            over: function(event, ui) {
                var $this = $(this);
            },
            drop: function(event, ui) {
                var caseNo=$(this).find('td:eq(0)').text();
                var servTechName=$(ui.draggable).find('td:eq(0)').text();
                updateDB(caseNo,servTechName);
            },
        });
    });
    function updateDB(caseNo,servTechName){
        alert("CaseNo>> "+caseNo+ " || servTechName>> "+servTechName);
        var caseObj=new sforce.SObject("Case");
        var stechQuery=sforce.connection.query("SELECT Id from Service_Technician__c Where Name ='"+servTechName+"' LIMIT 1");
        stRecord=stechQuery.getArray('records');
        stechId=stRecord[0].Id;
        var caseQuery=sforce.connection.query("SELECT Id from Case Where CaseNumber ='"+caseNo+"' LIMIT 1");
        caseRecord=caseQuery.getArray('records');
        caseObj.Id=caseRecord[0].Id;
        caseObj.Assigned_To__c=stechId;
        alert("stechObj>> "+caseObj.Assigned_To__c);
        sforce.connection.update([caseObj]);
        window.location.reload(); 
    }

而不是使用此window.location.reload();，如何单独刷新表。

Answer 1

您可以通过 Loading Page Fragments .文档

function RefreshTable() {
       $( "#YourTaleID" ).load( "yourpage.html #YourTaleID" );
   }