不和谐机器人YouTube搜索，等待异步功能的答案

Question

>我已经建立了一个不和谐，但使用javascript，我有一个命令，我希望能够搜索YouTube视频并在语音频道中播放第一个结果。

我正在使用 discordjs 和 discord-youtube-api 库。

此代码查找要搜索的命令。args 数组是搜索查询

else if (command === 'search') {
isReady = false;
if (message.channel.type !== 'text') return;
const { voiceChannel } = message.member;
if (!voiceChannel) {
return message.reply('please join a voice channel first!');
}
voiceChannel.join().then(connection => {
const stream = ytdl(searchYouTubeAsync(args), { filter: 'audioonly' });
const dispatcher = connection.playStream(stream);
dispatcher.on('end', () => voiceChannel.leave());
isReady = true;
})
};

这是使用 youtube api 搜索视频并返回其 url 的函数。

async function searchYouTubeAsync(args) {
var video = await youtube.searchVideos(args.toString().replace(/,/g,' '));
console.log(video.url);
console.log(typeof String(video.url));
return String(video.url);
}

尝试该命令时，我确实收到以下错误消息。

(node:13141) UnhandledPromiseRejectionWarning: TypeError [ERR_INVALID_ARG_TYPE]: The "url" argument must be of type string. Received type object
at Url.parse (url.js:146:11)
at Object.urlParse [as parse] (url.js:140:13)
at Object.exports.getURLVideoID (/Users/alexanderhoerl/Developer/discord-music-bot/node_modules/ytdl-core/lib/util.js:248:20)
at Object.exports.getVideoID (/Users/alexanderhoerl/Developer/discord-music-bot/node_modules/ytdl-core/lib/util.js:279:20)
at getInfo (/Users/alexanderhoerl/Developer/discord-music-bot/node_modules/ytdl-core/lib/info.js:46:17)
at ytdl (/Users/alexanderhoerl/Developer/discord-music-bot/node_modules/ytdl-core/lib/index.js:17:3)
at voiceChannel.join.then.connection (/Users/alexanderhoerl/Developer/discord-music-bot/index.js:89:24)
at process._tickCallback (internal/process/next_tick.js:68:7)
(node:13141) UnhandledPromiseRejectionWarning: Unhandled promise rejection. This error originated either by throwing inside of an async function without a catch block, or by rejecting a promise which was not handled with .catch(). (rejection id: 1)
(node:13141) [DEP0018] DeprecationWarning: Unhandled promise rejections are deprecated. In the future, promise rejections that are not handled will terminate the Node.js process with a non-zero exit code.

我想问题是音乐机器人在搜索YouTube功能找到链接之前尝试加载流，因此没有提供有效的URL。虽然我不知道如何解决这个问题，因为该功能需要异步才能等待 youtube 搜索结果。

Answer 1

您可以在async函数中运行它：

voiceChannel.join().then(async connection => {
let url = await searchYouTubeAsync(args);
let stream = ytdl(url, { filter: 'audioonly' });
let dispatcher = connection.playStream(stream);
dispatcher.on('end', () => voiceChannel.leave());
isReady = true;
})

Answer 2

我几乎可以肯定现在这是不真实的。但是，这是解决方案：

const stream = ytdl(searchYouTubeAsync(args).toString(), { filter: 'audioonly' });

xxx.toString(( 当我在使用 ytdl 时遇到同样的麻烦时，我感到很痛苦。