如何在 c# 中创建 SOAP 消息?

Question

>我正在寻找一个在 c# 中创建肥皂消息， 在这里，我使用命令提示符下的命令创建了一个客户端，现在尝试创建肥皂消息，但是我对这个概念很陌生，因此无法找到正确的方法，所以有人对此有想法吗？

Answer 1

创建 SOAP 请求的示例代码

using System;  
using System.IO;  
using System.Net;  
using System.Xml;  
namespace UsingSOAPRequest  
{  
public class Program  
{  
static void Main(string[] args)  
{  
//creating object of program class to access methods  
Program obj = new Program();  
Console.WriteLine("Please Enter Input values..");  
//Reading input values from console  
int a = Convert.ToInt32(Console.ReadLine());  
int b = Convert.ToInt32(Console.ReadLine());  
//Calling InvokeService method  
obj.InvokeService(a, b);  
}  
public void InvokeService(int a, int b)  
{  
//Calling CreateSOAPWebRequest method  
HttpWebRequest request = CreateSOAPWebRequest();  
XmlDocument SOAPReqBody = new XmlDocument();  
//SOAP Body Request  
SOAPReqBody.LoadXml(@"<?xml version=""1.0"" encoding=""utf-8""?>  
<soap:Envelope xmlns:soap=""http://schemas.xmlsoap.org/soap/envelope/"" xmlns:xsi=""http://www.w3.org/2001/XMLSchema-   instance"" xmlns:xsd=""http://www.w3.org/2001/XMLSchema"">  
<soap:Body>  
<Addition xmlns=""http://tempuri.org/"">  
<a>" + a + @"</a>  
<b>" + b + @"</b>  
</Addition>  
</soap:Body>  
</soap:Envelope>");  

using (Stream stream = request.GetRequestStream())  
{  
SOAPReqBody.Save(stream);  
}  
//Geting response from request  
using (WebResponse Serviceres = request.GetResponse())  
{  
using (StreamReader rd = new StreamReader(Serviceres.GetResponseStream()))  
{  
//reading stream  
var ServiceResult = rd.ReadToEnd();  
//writting stream result on console  
Console.WriteLine(ServiceResult);  
Console.ReadLine();  
}  
}  
}  
public HttpWebRequest CreateSOAPWebRequest()  
{  
//Making Web Request  
HttpWebRequest Req = (HttpWebRequest)WebRequest.Create(@"http://localhost/Employee.asmx");  
//SOAPAction  
Req.Headers.Add(@"SOAPAction:http://tempuri.org/Addition");  
//Content_type  
Req.ContentType = "text/xml;charset="utf-8"";  
Req.Accept = "text/xml";  
//HTTP method  
Req.Method = "POST";  
//return HttpWebRequest  
return Req;  
}  
}  
}