public interface IInterface<T>
{
void Handle(T message);
}
public class A: IInterface<T>
{
void Handle(T Message) {}
}
public class B: IInterface<T>
{
void Handle(T Message) {}
}
客户:
public void Execute<T>(T message)
{
var commandHandlers = DependencyResolver.Current.GetServices(typeof(IInterface<T>)).Cast<IInterface<T>>();
// The above line will give a list of implementation class of IInterface.
foreach (var commandHandler in commandHandlers)
{
commandHandler.Handle(message);
}
}
有没有办法先执行 B 类实现,然后执行 A 类实现作为第二个实现?
您可以添加 order 属性来控制它:
public interface IInterface<T>
{
void Handle(T message);
int Order {get;}
}
public class A: IInterface<T>
{
void Handle(T Message) {}
public int Order => 1;
}
public class B: IInterface<T>
{
void Handle(T Message) {}
public int Order => 0;
}
foreach (var commandHandler in commandHandlers.OrderBy(o=>o.Order))
{
commandHandler.Handle(message);
}