打印修改日期与 bash

Question

我在获取bash脚本来打印文件的修改日期时遇到了一些问题，这是我的代码：

files=$(ls -R)    
for file in ${files}
do
  modification=$(date +%D -r ${file})
    echo ${modification}
done

问题是，当我运行脚本时，与脚本打印日期相同的所有内容，但如果文件低于或更高级别，则会出现错误，如以下输出所示：

File .: was modified on 
File 1.txt was modified on 02/05/19
File 2.txt was modified on 02/05/19
File 3.txt was modified on 02/05/19
File folder was modified on 02/05/19
File GetFiles.sh was modified on 02/05/19
date: ./folder:: No such file or directory
File ./folder: was modified on 
date: folder1.txt: No such file or directory
File folder1.txt was modified on 
date: folder2.txt: No such file or directory
File folder2.txt was modified on 
date: folder3.txt: No such file or directory
File folder3.txt was modified on 

Answer 1

shopt -s globstar
for i in **; do date +"$i was modified on %D" -r "$i"; done

从man bash ：

globstar ： 如果设置，则路径名扩展上下文中使用的模式 ** 将匹配所有文件和零或 更多目录和子目录。 如果模式后跟/，则仅目录和 子目录匹配。

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请参阅：help shopt