特征:优化入口周围的越界矩阵块/切片



作为个人项目的一部分,我想优化以下函数,使其尽快运行。任何性能提升都很重要,因为程序其余部分的性能都取决于它。

目前,我正在使用 Eigen 的 block(( 函数,但由于负索引和越界索引不是有效的参数,因此我使用一些额外的代码来仅 block(( 必要的数据。

这是我试图优化的函数;它试图在给定的矩阵条目周围提取一个子矩阵。目标是然后对生成的矩阵进行哈希处理(使用 boost hash_combine的变体(,并在哈希表中查找它。

优化功能

#include <iostream>
#include <Eigen/Dense>
using namespace Eigen;
/// Returns a subsection from a matrix given the center and radius of the section. Fills space outside base matrix bounds with 0.
/// param baseMatrix: The matrix from which to take a section. Entires are integers, either 0 or 1.
/// param centerRow: The row serving as the center of the subsection.
/// param centerCol: The column serving as the center of the subsection.
/// param radius: The radius of the subsection, including the center entry.
/// return A matrix of the same type as the input matrix of size radius*2-1, representing the slice of the input matrix around the provided center coordinate.
Eigen::MatrixXi GetMatrixSection(const MatrixXi &baseMatrix, int centerRow, int centerCol, int radius)
{
    //== Constraints ==
    // baseMatrix, both dimensions can be between 1 and maxInt, but will generally be in range [3, 25] matrix is usually but not always square
    // 0 <= centerRow <= baseMatrix.rows()-1
    // 0 <= centerCol <= baseMatrix.cols()-1
    // 1 <= radius <= max(baseMatrix.rows(), baseMatrix.cols())
    //    This specific implementation of the function allows for radius of any size > 0
    // Create Base Matrix to fill
    int nSize = radius * 2 - 1; // Size of resulting matrix
    MatrixXi result = Eigen::MatrixXi().Constant(nSize, nSize, 0);
    // Get indices of the top-left corner for the block operation
    int lowerRowBound = centerRow - (radius-1);
    int lowerColBound = centerCol - (radius-1);
    // Get the top-left corner of baseMatrix
    int upperLeftCopyableRow = std::max(0, lowerRowBound);
    int upperLeftCopyableCol = std::max(0, lowerColBound);
    // Determine how many rows we need to take from the baseMatrix
    int numCopyableRows = std::min((int)baseMatrix.rows()-upperLeftCopyableRow, std::min(0, lowerRowBound)+nSize);
    int numCopyableCols = std::min((int)baseMatrix.cols()-upperLeftCopyableCol, std::min(0, lowerColBound)+nSize);
    if(numCopyableRows <= 0 || numCopyableCols <= 0) return result; // if it is impossible to copy anything from result, don't try
    // Copy all data we can from the baseMatrix
    MatrixXi copiedBlock = baseMatrix.block(upperLeftCopyableRow, upperLeftCopyableCol, numCopyableRows, numCopyableCols);
    // Copy the data from baseMatrix into resulting matrix
    result.block(upperLeftCopyableRow-lowerRowBound, upperLeftCopyableCol-lowerColBound,
                 (int)copiedBlock.rows(), (int)copiedBlock.cols()) = copiedBlock;
    // Return resulting matrix
    return result;
}

我使用以下代码来测试上述函数的效率。

函数的时序代码

int TestGetMatrixSection(MatrixXi matrixToTest, int trials=1)
{
    volatile int result = 0;
    for(int t = 0; t < trials; ++t) {
        for (int i = 1; i <= std::max(matrixToTest.rows(), matrixToTest.cols()); ++i) {
            for (int j = 0; j < matrixToTest.rows(); ++j) {
                for (int k = 0; k < matrixToTest.cols(); ++k) {
//                    std::cout << GetMatrixSection(matrixToTest, j, k, i) << "/n/n"; // printout
                    result += GetMatrixSection(matrixToTest, j, k, i).cols();
                }
            }
        }
    }
    return result;
}
int main()
{
    MatrixXi m = Eigen::MatrixXi(4, 5);
    m<< 1, 0, 0, 0, 1,
        1, 1, 0, 0, 1,
        1, 0, 1, 1, 0,
        1, 0, 0, 1, 0;
    auto startTime = std::chrono::steady_clock::now();
    TestGetMatrixSection(m, 10000);
    std::cout << std::chrono::duration_cast<std::chrono::milliseconds>(std::chrono::steady_clock::now()-startTime).count() << " millisecondsn";
    return 0;
}

目前该功能可以工作,但我担心性能是一个问题,它会被调用数百万次。

预期输出

Example 3x3 matrix
[[1, 0, 1],      
 [1, 1, 0],
 [0, 1, 0]]

row index 1, col index 1, radius 2
[[1, 0, 1],      
 [1, 1, 0],
 [0, 1, 0]]

row index 0, col index 0, radius 2
[[0, 0, 0],      
 [0, 1, 0],
 [0, 1, 1]]

row index 2, col index 2, radius 2
[[1, 0, 0],      
 [1, 0, 0],
 [0, 0, 0]]

row index 0, col index 0, radius 3
[[0, 0, 0, 0, 0],
 [0, 0, 0, 0, 0],
 [0, 0, 1, 0, 1],
 [0, 0, 1, 1, 0],
 [0, 0, 0, 1, 0]]

假设baseMatrix的大小没有变化,并且您知道一个合理的上部radius我建议将该矩阵存储到一个更大的矩阵中,该矩阵在每侧都扩展为 0 条目。实现这一点的一种可能性:

template<class S>
struct ExtendedMatrix{
    typedef Eigen::Matrix<S,Eigen::Dynamic, Eigen::Dynamic> MatS;
    typedef Eigen::Ref<MatS> Ref;
    typedef Eigen::Ref<MatS const> RefC;
    // read/write reference to baseMatrix:
    Ref getBaseMatrix() {
        return storage.block(maxR-1, maxR-1, storage.rows()-2*maxR+1, storage.cols()-2*maxR+1);
    }
    // read-only reference to baseMatrix:
    RefC getBaseMatrix() const {
        return storage.block(maxR-1, maxR-1, storage.rows()-2*maxR+1, storage.cols()-2*maxR+1);
    }
    // constructor. Takes an initial matrix and a maximum radius.
    template<class Derived>
    ExtendedMatrix(Eigen::MatrixBase<Derived> const& base, int maxRadius)
        : maxR(maxRadius), storage(base.rows()+2*maxR-1, base.cols()+2*maxR-1)
    {
        storage.setZero();
        getBaseMatrix() = base;
    }
    // method to get a (read-only) block of size 2radius-1 around a given coordinate
    // entries outside the original matrix are filled with 0s.
    RefC getMatrixSection(int centerRow, int centerCol, int radius) const
    {
        assert(radius <= maxR);
        int offset = maxR-radius;
        return storage.block(centerRow+offset, centerCol+offset, 2*radius-1, 2*radius-1);
    }
protected:
    int maxR;
    MatS storage;
};

像这样使用它:

int TestGetMatrixSection(Eigen::MatrixXi const & matrixToTest, int trials=1)
{
    int maxR = std::max(matrixToTest.rows(), matrixToTest.cols());
    ExtendedMatrix<int> eMat(matrixToTest, maxR);
    int result = 0;
    for(int t = 0; t < trials; ++t) {
        // eMat.getBaseMatrix().setRandom(); // or change individual entries ...
        for (int i = 1; i <= std::max(matrixToTest.rows(), matrixToTest.cols()); ++i) {
            for (int j = 0; j < matrixToTest.rows(); ++j) {
                for (int k = 0; k < matrixToTest.cols(); ++k) {
//                    std::cout << GetMatrixSection(matrixToTest, j, k, i) << "/n/n"; // printout
                    result += eMat.getMatrixSection(j, k, i).cols();
                }
            }
        }
    }
    return result;
}

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