编辑文本输入的十进制格式问题

Question

您好，我正在编写这个程序以获取用户输入并将格式设置为 0,000.00 例如 当我尝试 5,768.80 时程序运行良好，但当我尝试 5,768.08 时则无法正常工作 如您所见，问题是我不能在任何其他数字之前将 0 放在美分的位置......这是我的代码：

package com.calculadorabss.gorydev.calculadorabolivaressoberanos;
import android.text.Editable;
import android.text.TextWatcher;
import android.widget.EditText;
import java.text.DecimalFormat;
import java.text.ParseException;
class NumberTextWatcher implements TextWatcher {
private DecimalFormat df;
private DecimalFormat dfnd;
private boolean hasFractionalPart;
private EditText et;
//Dar formato al texto de entrada separando por comas
public NumberTextWatcher(EditText et)
{
df = new DecimalFormat("#,###,##");
df.setDecimalSeparatorAlwaysShown(true);
dfnd = new DecimalFormat("#,###,##");
this.et = et;
hasFractionalPart = false;
}
@SuppressWarnings("unused")
private static final String TAG = "NumberTextWatcher";
public void afterTextChanged(Editable s)
{
et.removeTextChangedListener(this);
try {
int inilen, endlen;
inilen = et.getText().length();
String v = s.toString().replace(String.valueOf(df.getDecimalFormatSymbols().getGroupingSeparator()), "");
Number n = df.parse(v);
int cp = et.getSelectionStart();
if (hasFractionalPart) {
et.setText(df.format(n));
} else {
et.setText(dfnd.format(n));
}
endlen = et.getText().length();
int sel = (cp + (endlen - inilen));
if (sel > 0 && sel <= et.getText().length()) {
et.setSelection(sel);
} else {
// place cursor at the end?
et.setSelection(et.getText().length() - 1);
}
} catch (NumberFormatException nfe) {
// do nothing?
} catch (ParseException e) {
// do nothing?
}
et.addTextChangedListener(this);
}
}

我希望程序能够接收 0 作为美分，例如 67,789.05

Answer 1

试试这个我认为它有效

public void afterTextChanged(Editable s)
{
et.removeTextChangedListener(this);
try {
int inilen, endlen;
inilen = et.getText().length();
String v = s.toString().replace(String.valueOf(df.getDecimalFormatSymbols().getGroupingSeparator()), "");
hasFractionalPart = v.contains(".");
Number n = df.parse(v);
int cp = et.getSelectionStart();
if (!hasFractionalPart) {
et.setText(dfnd.format(n));
}
endlen = et.getText().length();
int sel = (cp + (endlen - inilen));
if (sel > 0 && sel <= et.getText().length()) {
et.setSelection(sel);
} else {
// place cursor at the end?
et.setSelection(et.getText().length() - 1);
}
} catch (NumberFormatException nfe) {
// do nothing?
} catch (ParseException e) {
// do nothing?
}
et.addTextChangedListener(this);
}