如果抛出异常，Java 将继续执行循环

Question

示例：假设我想打开一个文件。如果我得到FileNotFoundException，我需要等待一段时间，然后再试一次。我怎样才能优雅地做到这一点？还是我需要使用嵌套try/catch块？

例：

public void openFile() {
    File file = null; 
    try {
        file = new <....>
    } catch(FileNotFoundException e) {
    }
    return file;
}

Answer 1

您可以使用

do { ... } while (file == null)结构。

File file = null; 
do {
    try {
        file = new <....>
    } catch(FileNotFoundException e) {
        // Wait for some time.
    }
} while (file == null);
return file;

Answer 2

public File openFile() {
  File file = null; 
  while (file == null) {
    try {
      file = new <....>
    } catch(FileNotFoundException e) {
      // Thread.sleep(waitingTime) or what you want to do
    }
  }
  return file;
}

请注意，这是一种有点危险的方法，因为除非文件最终出现，否则无法爆发。您可以添加一个计数器并在尝试一定次数后放弃，例如：

while (file == null) {
  ...
  if (tries++ > MAX_TRIES) {
    break;
  }
}

Answer 3

public File openFile() {
    File file = null; 
    while(true){
      try {
          file = new <....>
      } catch(FileNotFoundException e) {
            //wait for sometime
      }
      if(file!=null){
               break;  
      }
    }
    return file;
 }