如何在批处理命令中仅获取文件名'for'而不是文件扩展名

Question

当使用此代码将视频上传到YouTube时，命名的标题末尾有文件扩展名（在本例中为.mp4）

for %%f in (*.mp4) do python --file="%%f" --title="%%f"

Answer 1

使用for %%f in (*.csv) do echo "%%~nf"

有关更多信息，请执行for /?。。这是你希望看到的部分

In addition, substitution of FOR variable references has been enhanced.
You can now use the following optional syntax:
%~I         - expands %I removing any surrounding quotes (")
%~fI        - expands %I to a fully qualified path name
%~dI        - expands %I to a drive letter only
%~pI        - expands %I to a path only
%~nI        - expands %I to a file name only
%~xI        - expands %I to a file extension only
%~sI        - expanded path contains short names only
%~aI        - expands %I to file attributes of file
%~tI        - expands %I to date/time of file
%~zI        - expands %I to size of file
%~$PATH:I   - searches the directories listed in the PATH
               environment variable and expands %I to the
               fully qualified name of the first one found.
               If the environment variable name is not
               defined or the file is not found by the
               search, then this modifier expands to the
               empty string