PyGame - 绘制像素并打印出其坐标

Question

这似乎是一个很容易回答的问题，但我只是一个需要快速帮助的初学者。

我正在尝试创建一个程序，当你点击pyGame窗口的某个地方时，它会打印出你用鼠标左键点击它的信息，并打印出按下它的坐标。我已经有了。我在绘制pyGame窗口上的像素时遇到了问题。基本上，我想让它在我按下pyGame窗口的地方画一个像素。

#!/usr/bin/env python
#import the module for use 
import pygame
#setting up some variables
running = 1
LEFT = 1 
#Set up the graphics area/screen
screen=pygame.display.set_mode((640,400))
#continuous loop to keep the graphics running
while running==1:
event=pygame.event.poll()
if event.type==pygame.QUIT:
running=0
pygame.quit()
elif event.type==pygame.MOUSEBUTTONDOWN and event.button==LEFT:
print "You pressed the left mouse button at (%d,%d)" %event.pos
elif event.type==pygame.MOUSEBUTTONUP and event.button==LEFT:
print "You released the left mouse button at (%d,%d)" %event.pos

Answer 1

当收到鼠标按下事件时，尝试设置每个像素的颜色。

elif event.type==pygame.MOUSEBUTTONDOWN and event.button==LEFT:
print "You pressed the left mouse button at (%d,%d)" %event.pos
screen.set_at((event.pos.x, event.pos.y), pygame.Color(255,0,0,255))

请注意，这将根据需要临时锁定和解锁曲面。

Answer 2

我将唯美主义的代码编辑为一个独立的工作示例：

根据您正在做的操作，获取/设置单个像素可能会很慢。(如果需要的话，还有Surfsarray和Pixelarray。)

import pygame
from pygame.locals import *
class Game(object):
done = False
def __init__(self, width=640, height=480):
pygame.init()
self.width, self.height = width, height
self.screen = pygame.display.set_mode((width, height))
# start with empty screen, since we modify it every mouseclick
self.screen.fill(Color("gray50"))
def main_loop(self):
while not self.done:
# events
events = pygame.event.get()
for event in events:
if event.type == pygame.QUIT: self.done = True
elif event.type == KEYDOWN:
if event.key == K_ESCAPE: self.done = True
elif event.type == MOUSEMOTION:
pass
elif event.type == MOUSEBUTTONDOWN and event.button == 1:
print "Click: ({})".format(event.pos)
self.screen.set_at(event.pos, Color("white"))
# draw
pygame.display.flip()

if __name__ == "__main__":
g = Game()
g.main_loop()