c＃diffgram到XElement，读者/作者混淆

Question

如何在Xlement中获得数据集的分布？（或xdocument）

我发现了如何在字符串中获取diffgram：

        // DataSet to Diffgram in a string:
        StringBuilder sb = new StringBuilder();
        XmlWriterSettings settings = new XmlWriterSettings { Indent = true, Encoding = Encoding.UTF8 };
        using (XmlWriter xw = XmlWriter.Create(sb, settings))
        {
            ds.WriteXml(xw, XmlWriteMode.WriteSchema);//XmlWriteMode.DiffGram
        }
        string str = sb.ToString();

，但是首先将diffgram的XML输出到字符串中，然后将其解析回XElement似乎很浪费。因此，我试图找出如何填充此代码中的丢失链接，该链接应该传输diffgram的XML，而不会转换为XML变量：

        // I have a DataSet filled with some data
        DataSet ds = new DataSet();
        ds.Tables.Add(ScanData);
        // I need the diffgram of the DataSet in an XElement
        XElement xe = null;
        XmlReader xr = xe.CreateReader();
        // I could live with output to XDocument, and extract the XElement later
        XDocument xd = new XDocument();
        XmlReader xrd = xd.CreateReader();
        // Q: How do I construct a stream that connects an XmlReader to ds.WriteXml()?
        Stream stream =  ...???... ;
        // This method creates the DiffGram output format to a stream
        ds.WriteXml(stream, XmlWriteMode.WriteSchema);//diffgram output

我希望找到我的代码问题的答案，甚至可能了解流/读者/作者的真正工作方式。

Answer 1

您需要一个从数据集写入xdocument的作者，而不是读者：

XDocument xd = new XDocument();
using (var writer = xd.CreateWriter())
{
    ds.WriteXml(writer, XmlWriteMode.WriteSchema); // XmlWriteMode.DiffGram
}