我有一个"商店"模块,我需要将其输出放在菜单中,该菜单由/catalog/catalog/view/themey/journal2/journal2/template/journal2/菜单/菜单/main/main.tpl
它的控制器在目录/控制器/journal2/menu.php
中我尝试的是:
<file path="catalog/controller/journal2/menu.php">
<operation>
<search><![CDATA[$this->template = $this->config->get('config_template') . '/template/journal2/menu/main.tpl';]]></search>
<add position="before"><![CDATA[
$data['ac_all_stores'] = $this->load->controller('module/store');
]]></add>
</operation>
</file>
和
<file path="catalog/controller/module/store.php">
<operation>
<search><![CDATA[return $this->load->view($this->config->get('config_template') . '/template/module/store.tpl', $data);]]></search>
<add position="after"><![CDATA[
$this->load->view($this->config->get('config_template') . 'template/journal2/menu/main.tpl', $data);
]]></add>
</operation>
</file>
但是这些都不是。在菜单的主体中仍然看不到模块的输出。预先感谢!
我设法通过放置
来解决这个问题 $this->data['ac_all_stores'] = $this->load->controller('module/store');
而不是
$data['ac_all_stores'] = $this->load->controller('module/store');