实现此部分
import random
def get_random_number():
return random.randrange(100, 1000)
def get_not_duplicated_random_number():
//enter your code here
result = None
return result
我需要使用get_random_number()
函数
您必须从每个数字中获取3位数字并进行比较。这样的东西:
import math
import random
def get_random_number():
return random.randrange(100, 1000)
numbers = [];
for i in range(0,3):
number = get_random_number();
e = math.floor(number/100);
d = math.floor((number-e*100)/10);
m = math.floor((number-e*100-d*10));
while (e == d or d == m or m == e):
number = get_random_number();
e = math.floor(number/100);
d = math.floor((number-e*100)/10);
m = math.floor((number-e*100-d*10));
numbers.append(number)
print(numbers)
如果您不想要重复的数字,则需要在不替换的情况下选择3位数字。这使这变得更加困难,因为0
不能是您的第一个数字:
from random import sample
from string import digits
from itertools import chain
digits = set(digits)
first = sample(digits, 1)
rest = sample(digits.difference(first), 2)
result = int(''.join(chain(first, rest)))
(您可以使用range(10)
而不是string.digits
来更快地做到这一点,但我觉得这更具说明性(