我使用DynamicDataDisplay
来进行绘图。我得到了一个错误消息:调用线程不能访问这个对象,因为当调试器达到以下行时,不同的线程拥有它:
Action AddLineGraph = delegate()
{
timeDomainPlotter.AddLineGraph(_ods,
new Pen(_curveColors[_statsEnableIndex[i]], 2),
new CirclePointMarker { Size = 5, Fill = _curveColors[_statsEnableIndex[i]] },
new PenDescription(Convert.ToString(j)));
};
this.Dispatcher.Invoke(System.Windows.Threading.DispatcherPriority.Normal, AddLineGraph);
我对此感到困惑,因为当我使用LineGraph
绘制plot时如下:
Action AddLineGraph = delegate()
{
timeDomainPlotter.AddLineGraph(_ods, 2, "Ch" + Convert.ToString(j) + _statsName[_statsEnableIndex[i]]);
};
this.Dispatcher.Invoke(System.Windows.Threading.DispatcherPriority.Normal, AddLineGraph);
运行良好。所以我想知道为什么画点标记给出错误信息?谢谢。
编辑:这里是我添加的更多代码,其中_curveColors
是定义的。
public void InitiatePlot()
{
// InitializeComponent();
// timeDomainPlotter.Legend.Remove();
_initialChildrenCount = timeDomainPlotter.Children.Count;
int count = timeDomainPlotter.Children.Count;
//do not remove the initial children
if (count > _initialChildrenCount)
{
for (int i = count - 1; i >= _initialChildrenCount; i--)
{
timeDomainPlotter.Children.RemoveAt(i);
}
}
// _curveColors = new System.Drawing.Color[_nMaxStatsPerChannel];
_curveColors = new Brush[_nMaxStatsPerChannel];
for (int i = 0; i < _nMaxStatsPerChannel; i++)
{
_curveColors[i] = new SolidColorBrush((Color)ColorConverter.ConvertFromString(_colorList[i]));
// _curveColors[i] = System.Drawing.Color.FromName(_colorList[i]);
}
_statsName = Enum.GetNames(typeof(Window1.ROISignalList));
//_statsEnableIndex = new int[_nActiveStatsPerChannel];
for (int j = 0; j < _nActiveChannels; j++) // init data source structure
{
// count = 0;
for (int i = 0; i < _nActiveStatsPerChannel; i++)
{
_ods = new ObservableDataSource<Point>();
_odsAll[j * _nActiveStatsPerChannel + i] = _ods; // _osdAll: C0S0 C0S1 C0S2 C1S0 C1S1 C1S2 ... C4S0 C4S1 C4S2
Action AddLineGraph = delegate()
{
timeDomainPlotter.AddLineGraph(_ods,
new Pen(_curveColors[_statsEnableIndex[i]], 2),
new CirclePointMarker { Size = 5, Fill = _curveColors[_statsEnableIndex[i]] },
new PenDescription(Convert.ToString(j)));
};
this.Dispatcher.Invoke(System.Windows.Threading.DispatcherPriority.Normal, AddLineGraph);
}
}
}
我找到原因了。就像SpaceghostAli提到的,_curveColors确实是导致这个错误的罪魁祸首。
我不得不说我没有完全弄清楚为什么,但是如果我用定义的颜色替换所有的_curveColors,问题就解决了。特别地,下面是给出错误的代码:
Action AddLineGraph = delegate()
{
timeDomainPlotter.AddLineGraph(_ods,
new Pen(_curveColors[_statsEnableIndex[i]], 2),
new CirclePointMarker { Size = 5, Fill = _curveColors[_statsEnableIndex[i]] },
new PenDescription(Convert.ToString(j)));
};
this.Dispatcher.Invoke(System.Windows.Threading.DispatcherPriority.Normal, AddLineGraph);
下面是没有错误的代码:
Action AddLineGraph = delegate()
{
timeDomainPlotter.AddLineGraph(_ods,
//new Pen(_curveColors[_statsEnableIndex[i]], 2),
new Pen( new SolidColorBrush(Colors.Transparent), 2),
new CirclePointMarker { Size = 5, Fill = new SolidColorBrush(Colors.Green) },
new PenDescription(Convert.ToString(j)));
};
this.Dispatcher.Invoke(System.Windows.Threading.DispatcherPriority.Normal, AddLineGraph);
,你可以看到只有_curveColors被更改为确定性的颜色。
我猜_curveColors不是在UI线程上创建的。您应该回溯并查看InitiatePlot是如何被调用的,并确保UI线程拥有_curveColors.