使用javaScript SDK登录Parse.com



不知道为什么登录不工作。以下是javaScript代码:

Parse.initialize("app id", "app key");
function fazerLogin() {
    var username = document.getElementById('usuario').value;
    var password = document.getElementById('senha').value;
    alert(username);
    alert(password);
    Parse.User.logIn(username, password, {
        success: function(user) {
            alert("deu certo");
            // Do stuff after successful login.
        },
        error: function(user, error) {
            alert("erro");
            alert(user + error);
            // The login failed. Check error to see why.
        }
    });
}
var botao = document.querySelector('#botao');
botao.onclick = fazerLogin;

函数被调用,因为我看到了带有正确登录名和密码的警报。我可以登录iOS sdk没有问题,但它不能在javaScript上工作,我不确定我错过了什么。在body内的html文档的末尾,我有:

     <!-- PARSE.COM JS -->
    <script src="assets/js/parse-1.2.18.js"></script>
    <script src="assets/js/login.js"></script>

即使我把用户名和密码作为字符串,如:Parse.User.logIn("username", "password", {,它仍然不起作用。

更新:

login工作时,我调用它的外部函数:

Parse.User.logIn("email", "PASS", {
        success: function(user) {
            console.log("Deu certo");
            console.log(user);
            return true;
        },
        error: function(user, error) {
            console.log(user + error);
            return false;
        }
    });
HTML表单

<form role="form" id="formulario-login">
                <div class="form-group has-feedback lg left-feedback no-label">
                  <input type="text" class="form-control no-border input-lg rounded" placeholder="Usuário" autofocus id="usuario">
                  <span class="fa fa-user form-control-feedback"></span>
                </div>
                <div class="form-group has-feedback lg left-feedback no-label">
                  <input type="password" class="form-control no-border input-lg rounded" placeholder="Senha" id="senha">
                  <span class="fa fa-unlock-alt form-control-feedback"></span>
                </div>
                <div class="form-group">
                  <div class="checkbox">
                    <label>
                      <input type="checkbox" class="i-yellow-flat"> Manter-me conectado.
                    </label>
                  </div>
                </div>
                <div class="form-group">
                    <button type="submit" class="btn btn-warning btn-lg btn-perspective btn-block" id="botao">LOGIN</button>
                </div>
            </form>

正如我们在评论中讨论的那样,问题是您使用的是<button type="submit"而不是<button type="button"

两者之间的核心区别在于,submit类型实际上会在执行函数之前提交表单和HTML表单中的数据,而button类型会给您一个不提交的按钮,但会触发分配给它的所有事件(例如您的onclick)。

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