计算棋盘的中心

Question

我试图打印一个 Reversi 宽，给定用户定义的行和列。在实现和打印电路板时，我在找到中心四件时遇到了一些麻烦。这是我到目前为止所拥有的：

def new_game_board(columns,rows) -> [[str]]:
    ''' Creates a new game board.  Initially, a game board has the size
    BOARD_COLUMNS x BOARD_ROWS and is comprised only of strings with the
    value NONE
    '''
    board = []
    for col in range(columns):
        board.append([])
        for row in range(rows):
            board[-1].append('*')
    black = (rows+1)*columns//2
    white = rows//2
    white = columns//2
    return board
def drawBoard(board,columns,rows):
    print('  '.join(map(lambda x: str(x + 1), range(columns))))
    for y in range(rows):
        print('  '.join(board[x][y] for x in range(columns)))

如何找到根据用户输入放置的新中心件？最终的板应如下所示：

1  2  3  4  5  6 
.  .  .  .  .  .
.  .  .  .  .  .
.  .  B  W  .  .
.  .  W  B  .  .
.  .  .  .  .  .
.  .  .  .  .  .

Answer 1

你有大小为columns x rows的矩形，所以中间在每个轴的中间：columns/2和rows/2。

import math
middle_start_row = math.floor(rows/2)
middle_start_col = math.floor(columns/2)