在Android上使用Prosody服务器创建多用户组(aSmack)失败并"Missing acknowledge of room creation"

Question

我正在安卓系统中开发XMPP聊天应用程序，使用Prosody作为XMPP server。我已经编写了创建Multi User Chat房间的代码，当我使用Openfire作为服务器时，它可以正常工作，但当我使用Prosody作为服务器时它会给我错误，如

Creation failed - Missing acknowledge of room creation.:即组已存在。但它对任何名称（新组名）都抛出相同的错误。

若我用muc.join(name);替换muc.create(name);，它将创建组。但是我无法配置组/房间属性。

下面是我的Probody配置文件：-

modules_enabled = {
-- Generally required
    "roster"; -- Allow users to have a roster. Recommended ;)
    "saslauth"; -- Authentication for clients and servers. Recommended if  you want to log in.
    --"tls"; -- Add support for secure TLS on c2s/s2s connections
    "dialback"; -- s2s dialback support
    "disco"; -- Service discovery
-- Not essential, but recommended
    "private"; -- Private XML storage (for room bookmarks, etc.)
    "vcard"; -- Allow users to set vCards
-- These are commented by default as they have a performance impact
    --"privacy"; -- Support privacy lists
    --"compression"; -- Stream compression
-- Nice to have
    "version"; -- Replies to server version requests
    "uptime"; -- Report how long server has been running
    "time"; -- Let others know the time here on this server
    "ping"; -- Replies to XMPP pings with pongs
    "pep"; -- Enables users to publish their mood, activity, playing music  and more
    "register"; -- Allow users to register on this server using a client  and change passwords
-- Admin interfaces
    "admin_adhoc"; -- Allows administration via an XMPP client that  supports ad-hoc commands
    --"admin_telnet"; -- Opens telnet console interface on localhost port  5582
-- HTTP modules
    "bosh"; -- Enable BOSH clients, aka "Jabber over HTTP"
    "http_files"; -- Serve static files from a directory over HTTP
-- Other specific functionality
    "groups"; -- Shared roster support
    --"announce"; -- Send announcement to all online users
    --"welcome"; -- Welcome users who register accounts
    --"watchregistrations"; -- Alert admins of registrations
    --"motd"; -- Send a message to users when they log in
    --"legacyauth"; -- Legacy authentication. Only used by some old  clients and bots.
};
 allow_registration = true -- Allow users to register new accounts
VirtualHost "localhost"
---Set up a MUC (multi-user chat) room server on conference.example.com:
Component "conference.localhost" "muc"

我的组创建代码是：-

                             MultiUserChat muc = new MultiUserChat(xmppConnection, room);
                          // Create the room
                          SmackConfiguration.setPacketReplyTimeout(2000);
                          String name = xmppConnection.getUser();
                          System.out.println("name:- " + name);
                          String name1 = name.substring(0, name.lastIndexOf("@"));
                          System.out.println("name1:- " + name1);
                          System.out.println("group name:- " + grpName);
                          muc.create(name1);
                          // Get the the room's configuration form
                          Form form = muc.getConfigurationForm();
                          // Create a new form to submit based on the original form
                          Form submitForm = form.createAnswerForm();
                          // Add default answers to the form to submit
                          for (Iterator<FormField> fields = form.getFields(); fields.hasNext();) {
                              FormField field = (FormField) fields.next();
                              if (!FormField.TYPE_HIDDEN.equals(field.getType()) && field.getVariable() != null) {
                                  // Sets the default value as the answer
                                  submitForm.setDefaultAnswer(field.getVariable());
                              }
                          }
                         // muc.sendConfigurationForm(submitForm);
                          Form f = new Form(Form.TYPE_SUBMIT);
                          try {
                               muc.sendConfigurationForm(f);
                          } catch (XMPPException xe) {
                               System.out.println( "Error on sendConfigurationForm:- " +  xe);
                          }
                          // Sets the new owner of the room
                          List<String> owners = new ArrayList<String>();
                          owners.add(xmppConnection.getUser());
                          submitForm.setAnswer("muc#roomconfig_roomowners", owners);
                          submitForm.setAnswer("muc#roomconfig_persistentroom", true);
                          muc.sendConfigurationForm(submitForm);

我哪里错了？

Answer 1

这是由韵律的MUC插件的非标准行为引起的。基本上，它的行为就像一个MUC房间已经存在，即使事实并非如此。

你必须有可能：

• 在这种情况下，使用Smack的（自4.0以来）MultiUserChat.createOrJoin（String）将成功。另请参见SMACK-557
• 将韵律的mod-MUC属性restrict_room_creation设置为true，将使韵律的行为符合XEP-45中的规定

由于要配置房间，唯一的选项是更改韵律的restrict_room_creation设置。

^{请注意，Smack的MUC代码中还有另一个问题，该问题将在Smack 4.1中解决，并且可能还会在韵律中实现一个变通方法。但我不认为这个问题与此有关，这些信息只是为了完整性。}