将文本行存储为链表，然后在C中颠倒它们的顺序

Question

我已经设置了一个赋值，将文本行存储到链表中的句号，并颠倒它们的顺序，而不打印句号。

到目前为止，我的代码是：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
struct node {
   char line[50];
   struct node *next;
};
int main()
{
   //intialise stuff
   char l[50];
   int i;
   struct node *head = NULL, *newNode, *current;
   head = (struct node *)calloc(1,sizeof(struct node));
   char c;
   //read in list reversed
   printf("Enter some lines followed by '.':n");
   while(c!='.'){
      i=0;
      do {
         c = getchar();
         if (c != '.') {
            l[i]=c;
            i++;
         }
         else
            {break;}
         } while (c!='n');
      newNode = (struct node *)calloc(1,sizeof(struct node));
      for (i=0;i<strlen(l);i++)
         newNode->line[i] = l[i];
      newNode->next=head;
      head = newNode;
   }

   //print reversed list
   current = head;
   while (current != NULL) {
        for (i=0;i<strlen(current->line);i++)
        printf("%c", current->line[i]);
        current = current->next;
   }
   return 0;
}

该代码适用于以下输入：

hello
there
world.

但是当我输入时

1234
4321
7777.

输出具有的奇怪正方形

  00
  01

在第一个数字上，如果我输入：

ricky
is
cool.

输出为：

cooly
is
ky
ricky

有人能帮我弄清楚是哪部分代码导致了这种情况吗？

Answer 1

用'\0'关闭字符串，否则strlen和pals将无法计算出实际大小。新行"\n"存储在字符串中，但head有一个额外的"。"处理。

const uint SZ = 50;
struct node { struct node * next; char line[SZ]; };
struct node * wnod, * head = 0;
uint idx;
char ch = 'n';
// read in list reversed
printf( "Enter some lines followed by '.':n" );
while( '.' != ch )
{
    wnod = ( struct node * ) calloc( 1, sizeof( struct node ) );
    wnod->next = head;
    for( idx = 0; idx < SZ - 1; ++idx )
    {
        ch = getchar();
        if( ( '.' != ch ) && ( 'n' != ch ) )
        { 
                    wnod->line[idx] =   ch;
        } else {    
                    wnod->line[idx] = ''; idx = SZ;
        }
    }
    head = wnod;
}
// print linked list
while( head )
{
    for( idx = 0; idx < strlen( head->line ); ++idx )
    {
        printf( "%c", head->line[idx] );
    }
    printf( "|n" );
    wnod = head; head = head->next; free( wnod );
}