我需要使用 XSLT(不幸的是版本 1..) 我试图通过比较子节点中的两个属性来过滤掉某些节点。
下面是 XML:
<?xml version="1.0" encoding="UTF-8"?>
<SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/">
<SOAP-ENV:Header xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/">
</SOAP-ENV:Header>
<SOAP-ENV:Body xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/">
<QueriesResponse xmlns="http://schemas.Movies.com/Movies">
<Films xmlns="http://schemas.Movies.com/Movies">
<Film>
<FilmPostings>
<FilmPosting>
<FilmPostingDates>
<FilmPostDate>2017-01-04T19:44:25.9530000-05:00</FilmPostDate>
<FilmActiveDate>2017-01-04T19:44:25.9530000-05:00</FilmActiveDate>
</FilmPostingDates>
</FilmPosting>
</FilmPostings>
</Film>
<Film>
<FilmPostings>
<FilmPosting>
<FilmPostingDates>
<FilmPostDate>2017-01-04T19:50:06.3830000-05:00</FilmPostDate>
<FilmActiveDate>2017-01-04T19:50:06.3100000-05:00</FilmActiveDate>
</FilmPostingDates>
</FilmPosting>
</FilmPostings>
</Film>
<Film>
<FilmPostings>
<FilmPosting>
<FilmPostingDates>
<FilmPostDate>2016-12-05T18:03:14.9830000-05:00</FilmPostDate>
<FilmActiveDate>2017-01-02T00:16:52.7570000-05:00</FilmActiveDate>
</FilmPostingDates>
</FilmPosting>
</FilmPostings>
</Film>
</Films>
</QueriesResponse>
</SOAP-ENV:Body>
</SOAP-ENV:Envelope>
这是我的转变:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns="http://schemas.Movies.com/Movies"
xmlns:m="http://schemas.Movies.com/Movies"
exclude-result-prefixes="m"
>
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" />
<!-- standard identity template -->
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<!-- This is mean to compare PostDate and ActiveDate, matching if different. It doesn't match any nodes in XML (but should match the final one). -->
<xsl:template match="m:Film[m:FilmPostings/m:FilmPosting/m:FilmPostingDates/m:FilmPostDate[1] [.!= m:FilmPostings/m:FilmPosting/m:FilmPostingDates/m:FilmActiveDate[1]]]">
</xsl:template>
<!-- This code does match the hard coded value (the second node). -->
<!--<xsl:template match="m:Film[m:FilmPostings/m:FilmPosting/m:FilmPostingDates/m:FilmPostDate[1] [.!= '2017-01-04T19:50:06.3830000-05:00']]">
</xsl:template>-->
</xsl:stylesheet>
因此,您将在注释掉的位中看到我可以与硬编码值进行匹配,所以我显然在正确的区域 - 我知道如果代码找到匹配项,它将排除整个 Film 节点。但是比较两个节点值不起作用。
我已经在比较的右侧尝试了各种变体,但它似乎无法获取 ActiveDate 的值。
要删除Film
元素,FilmPostDate
和FilmActiveDate
,您实际上可以将条件嵌套在匹配属性中
<xsl:template
match="m:Film[m:FilmPostings/m:FilmPosting/m:FilmPostingDates[m:FilmPostDate = m:FilmActiveDate]]" />
这假设每个Film
只有一组FilmPostDate
和FilmActiveDate
元素。如果有多个集合,您可以尝试删除所有匹配项都相同的元素Film
(或者更确切地说,没有不同的匹配项)。
<xsl:template
match="m:Film[not(m:FilmPostings/m:FilmPosting/m:FilmPostingDates[m:FilmPostDate != m:FilmActiveDate])]" />