包装类时不向 JSON 添加"@class" ID @JsonTypeInfo也@JsonTypeInfo

Question

我正在尝试序列化一个"持有者"类，该类中有一个值，其类型派生自泛型。 即"类HasValue"内部有一个"私有A值"。

此外，我还有接口"Inf"和一个实现该接口的具体类"InfCls"。界面标有@JsonTypeInfo，并被告知创建一个"@class"字段。

如果持有者类没有@JsonTypeInfo，一切正常。但是当我补充说它坏了。

注意：虽然在这种情况下我不需要@JsonTypeInfo（因为持有者始终是一个具体的类），但在需要时会出现同样的问题，所以我选择这个作为更简单的例子。

以下为：

import static org.junit.Assert.assertEquals;
import java.util.Objects;
import org.junit.Test;
import com.fasterxml.jackson.annotation.JsonAutoDetect;
import com.fasterxml.jackson.annotation.JsonCreator;
import com.fasterxml.jackson.annotation.JsonProperty;
import com.fasterxml.jackson.annotation.JsonTypeInfo;
import com.fasterxml.jackson.annotation.JsonTypeInfo.As;
import com.fasterxml.jackson.databind.JavaType;
import com.fasterxml.jackson.databind.ObjectMapper;
public class SerializationIssues {
    // No @JsonTypeInfo on HasValue
    @Test
    public void json_HasValue_Inf_javaType() throws Exception {
        HasValue<Inf> object = new HasValue<>(new InfCls(1));
        ObjectMapper objectMapper = new ObjectMapper();
        JavaType javaType = objectMapper.getDeserializationConfig().getTypeFactory().constructParametricType(HasValue.class, Inf.class);
        String serialized = objectMapper.writerFor(javaType).writeValueAsString(object);
        HasValue<?> deserialized = objectMapper.readValue(serialized, javaType);
        assertEquals(object, deserialized);
    }
    // @JsonTypeInfo on HasValueId
    @Test
    public void json_HasValueId_Inf_javaType() throws Exception {
        HasValueId<Inf> object = new HasValueId<>(new InfCls(1));
        ObjectMapper objectMapper = new ObjectMapper();
        JavaType javaType = objectMapper.getDeserializationConfig().getTypeFactory().constructParametricType(HasValueId.class, Inf.class);
        String serialized = objectMapper.writerFor(javaType).writeValueAsString(object);
        HasValueId<?> deserialized = objectMapper.readValue(serialized, javaType);
        assertEquals(object, deserialized);
    }
    // ===== An interface and impl to test @JsonTypeInfo =====
    @JsonTypeInfo(use = JsonTypeInfo.Id.MINIMAL_CLASS, include = As.PROPERTY, property = "@class")
    public static interface Inf {
    }
    @JsonAutoDetect(fieldVisibility = JsonAutoDetect.Visibility.ANY, isGetterVisibility = JsonAutoDetect.Visibility.NONE, getterVisibility = JsonAutoDetect.Visibility.NONE, setterVisibility = JsonAutoDetect.Visibility.NONE)
    public static class InfCls implements Inf {
        private int val;
        @JsonCreator
        public InfCls(@JsonProperty("val") int val) {
            this.val = val;
        }
        @Override
        public String toString() {
            return "InfCls [val=" + val + "]";
        }
        @Override
        public int hashCode() {
            return 31 * 1 + val;
        }
        @Override
        public boolean equals(Object obj) {
            if (this == obj)
                return true;
            if (obj == null)
                return false;
            if (getClass() != obj.getClass())
                return false;
            InfCls other = (InfCls) obj;
            if (val != other.val)
                return false;
            return true;
        }
    }
    // ===== A class that has a value =====
    @JsonAutoDetect(fieldVisibility = JsonAutoDetect.Visibility.ANY, isGetterVisibility = JsonAutoDetect.Visibility.NONE, getterVisibility = JsonAutoDetect.Visibility.NONE, setterVisibility = JsonAutoDetect.Visibility.NONE)
    public static class HasValue<A> {
        private final A val;
        @JsonCreator
        public HasValue(@JsonProperty("val") A val) {
            this.val = Objects.requireNonNull(val);
        }
        public A get() {
            return val;
        }
        @Override
        public String toString() {
            return "HasValue [val=" + val + "]";
        }
        @Override
        public int hashCode() {
            return 31 * 1 + ((val == null) ? 0 : val.hashCode());
        }
        @Override
        public boolean equals(Object obj) {
            if (this == obj)
                return true;
            if (obj == null)
                return false;
            if (getClass() != obj.getClass())
                return false;
            HasValue<?> other = (HasValue<?>) obj;
            if (val == null) {
                if (other.val != null)
                    return false;
            } else if (!val.equals(other.val))
                return false;
            return true;
        }
    }
    @JsonTypeInfo(use = JsonTypeInfo.Id.MINIMAL_CLASS, include = JsonTypeInfo.As.PROPERTY, property = "@class")
    @JsonAutoDetect(fieldVisibility = JsonAutoDetect.Visibility.ANY, isGetterVisibility = JsonAutoDetect.Visibility.NONE, getterVisibility = JsonAutoDetect.Visibility.NONE, setterVisibility = JsonAutoDetect.Visibility.NONE)
    public static class HasValueId<A> {
        private final A val;
        @JsonCreator
        public HasValueId(@JsonProperty("val") A val) {
            this.val = Objects.requireNonNull(val);
        }
        public A get() {
            return val;
        }
        @Override
        public String toString() {
            return "HasValue [val=" + val + "]";
        }
        @Override
        public int hashCode() {
            return 31 * 1 + ((val == null) ? 0 : val.hashCode());
        }
        @Override
        public boolean equals(Object obj) {
            if (this == obj)
                return true;
            if (obj == null)
                return false;
            if (getClass() != obj.getClass())
                return false;
            HasValueId<?> other = (HasValueId<?>) obj;
            if (val == null) {
                if (other.val != null)
                    return false;
            } else if (!val.equals(other.val))
                return false;
            return true;
        }
    }
}

Answer 1

一旦遇到@JsonTypeInfo注释，您引导时使用的序列化程序就会被推开，并且您提供的类型信息正在丢失。

有几种方法可以解决此问题。您可以在类中提供显式类型信息：

public static class HasValueId<A extends Inf> {
    private final A val;

这将允许杰克逊通过内省确定字段类型并找到您的第二个注释。

或者您可以使用 @JsonTypeInfo 注释通用字段：

public static class HasValueId<A> {
    @JsonTypeInfo(use = JsonTypeInfo.Id.MINIMAL_CLASS, include = As.PROPERTY, property = "@class")
    private final A val; 

。这将避免在界面上进行注释的需要。

完成此操作后，您将不再需要键入您的编写器; 普通的旧objectMapper.writeValueAsString(object);将起作用。