我需要允许用户为他们的帖子选择标签,但从封闭列表中选择(假设只有管理员可以添加新标签,或者它们是以其他方式预定义的)。每个帖子可以有很多标签,所以它需要是多选择器的。不幸的是,添加select2 rails后,标签无法保存在DB中。我该怎么修?这对我不起作用。
PostsController:
class PostsController < ApplicationController
before_action :find_post, only: [:show, :edit, :update, :destroy]
before_action :authenticate_user!, only: [:new, :create, :edit, :update, :destroy]
def index
@posts = Post.page(params[:page]).per(10)
@tags = ActsAsTaggableOn::Tag.all
end
def new
@post = current_user.posts.new
@tags = ActsAsTaggableOn::Tag.all
end
def create
@post = current_user.posts.new(post_params)
if @post.save
redirect_to @post, notice: _('Post created')
else
render :new, notice: _('Something went wrong')
end
end
def show
@tags = ActsAsTaggableOn::Tag.all
end
def edit
authorize @post
@tags = ActsAsTaggableOn::Tag.all
end
def update
if @post.update(post_params)
redirect_to @post, notice: _('Post updated')
else
render :edit, notice: _('Something went wrong')
end
end
def destroy
authorize @post
if @post.destroy
redirect_to root_path, notice: _('Post deleted')
else
redirect_to @post, notice: _('Something went wrong')
end
end
private
def post_params
params.require(:post).permit(:title, :header, :content, :tag_list)
end
def find_post
@post = Post.friendly.find(params[:id])
end
end
型号:
class Post < ActiveRecord::Base
extend FriendlyId
friendly_id :title, use: :slugged
acts_as_ordered_taggable_on :tags
belongs_to :user
validates :title, :header, :content, presence: true
validates :title, uniqueness: true
end
视图:
= simple_form_for @post do |f|
= f.input :title
= f.input :header
= f.input :content, input_html: { rows: 10 }
= f.input :tag_list, collection: @tags, input_html: { multiple: true, class: 'tags' }
= f.submit 'Save', class: 'btn btn-warning'
= link_to _('Back'), :back
application.js:
$(document).ready(function(){
$('.tags').select2({
placeholder: 'Click to select',
theme: 'bootstrap'
});
});
嗯,这比我想象的要容易得多。我所要做的就是允许tag_list
作为数组tag_list: []
(默认语法:tag_list
不会在DB中保存标记,正如这里和这里所描述的那样),但只有这个更改导致了奇怪的行为——保存标记id而不是名称。第二件事,在上面的链接中没有提到,是明确定义选择器的标签和值方法(这很重要,因为在默认情况下,它会传递标签的id,而不是标签名称,所以它会创建名称与以前标签的id相同的新标签)。
控制器内:
def post_params
params.require(:post).permit(:title, :header, :content, tag_list: [])
end
视图中:
= simple_form_for @post do |f|
= f.input :title
= f.input :header
= f.input :content, input_html: { rows: 10 }
= f.input :tag_list, collection: @tags, value_method: :name, label_method: :name, input_html: { multiple: true, class: 'tags' }
= f.submit 'Save', class: 'btn btn-warning'
= link_to _('Back'), :back