let parent = path[row-1]
let child = path[row]
let indexOfChild = matrix[parent.objectId!]!.index(of: child)
print("indexOfChild = (indexOfChild)")
print("keyValuePair = (matrix[parent.objectId!]!)")
print("child = (child)")
let indexAfter = matrix[parent.objectId!]!.index(after: indexOfChild!)
结果,我将此信息打印在控制台中。
如您所见,"child"(这是带有 argumentText 的参数对象:"example"(存在于 keyValuePair 中(它们具有相同的 objectId(。然而,它在keyValuePair中的索引在控制台中显示为零。显然,仅仅是区别:"child"旁边有"0x608000333f60">,而keyValuePair中的第二个参数对象有"0x600000321a40"。
我不知道这些的目的是什么以及如何计算它们,但在我看来,索引为零,因为这些代码彼此不同
我一直在尝试修复它太久了。有人可以帮我度过难关吗?
indexOfChild = nil
keyValuePair = [<Argument: 0x608000334e60, objectId: IG9ekqMRw9, localId: (null)> {
ACL = "<PFACL: 0x60800042f200>";
argumentText = "the only thing is I can't get over how I feel when it ";
creatorId = hWRXoRvnYd;
level = 4;
parentId = j7GkpwUKsm;
reach = 0;
threadId = Dtq632QYJ2;
}, <Argument: 0x600000321a40, objectId: 56AsB1juNP, localId: (null)> {
ACL = "<PFACL: 0x600000235440>";
argumentText = "example ";
creatorId = hWRXoRvnYd;
level = 4;
parentId = j7GkpwUKsm;
reach = 0;
threadId = Dtq632QYJ2;
}]
child = <Argument: 0x608000333f60, objectId: 56AsB1juNP, localId: (null)> {
ACL = "<PFACL: 0x608000235540>";
argumentText = "example ";
creatorId = hWRXoRvnYd;
level = 4;
parentId = j7GkpwUKsm;
reach = 0;
threadId = Dtq632QYJ2;
}
fatal error: unexpectedly found nil while unwrapping an Optional value
0x608000333f60 和 0x600000321a40 值是相关变量的内存地址位置。由于地址位置不同,我相信两个子实例被视为两个单独的值,并且可能不会匹配。这可能是您遇到的问题。
最好通过唯一 ID 值检查子实例的父实例,以便可以正确匹配父数组中的子实例。这有意义吗?
您可以通过以下方式找到子项的索引:
var index = -1
var found = false
for chld in matrix[parent.objectId!]! {
index = index + 1
if chld.objectId == child.objectId {
found = true
break
}
}
if found {
// The index value at this point is the index for the child
}
您也可以简单地过滤子数组,以在父数组中找到与child
变量具有相同 objectId 的子数组,然后从子数组中找到索引,如下所示:
let chld = matrix[parent.objectId!]!.filter{ $0.objectId == child.objectId }.first
let indexOfChild = matrix[parent.objectId!]!.index(of: chld)