java中并行数组的并排显示

Question

我是java新手，我已经编写了代码来显示以下并行数组的值:

short[] Years = {1995, 1997, 1998,1999, 2000, 2001, 2002, 2003, 2004, 2005, 2006, 2007, 2008, 2009, 2010, 2011, 2012};
String[] Months = {"January", "February", "June", "January", "March", "June", "July", "August", "September", "March", "May", "January", "March", "July", "November", "March", "June"};

当前当我运行它时，它们显示在彼此的顶部。我正试着让它们并排显示。我该怎么做呢?

这段代码用来显示它们:

System.out.println("Years");
for(short temp: years)
{
System.out.println(temp);
}
System.out.println("Months");
for(String temp: months)
{
System.out.println(temp);
}

Answer 1

如果两者长度相等:

for (int i = 0; i < Years.length; i++) {
    System.out.println(Years[i] + 't' + Months[i]);
}

Answer 2

try this:

int length = Years.length > Months.length ? Months.length : Years.length;
for(int index = 0; index < length; index++) {
    System.out.println(Years[index] + 't' + Months[index]);
}

我建议你读一下

Answer 3

你可以这样做:

 short[] years = {1995, 1997, 1998,1999, 2000, 2001, 2002, 2003, 2004, 2005, 2006, 2007, 2008, 2009, 2010, 2011, 2012};
    String[] winners = {"January", "February", "June", "January", "March", "June", "July", "August", "September", "March", "May", "January", "March", "July", "November", "March", "June"};
    System.out.println("Years"+"t"+"Premiers");
    int i = years.length-1;
    int j= winners.length-1;
    int  k=0;
int l=0;
    do{
            i--;
            j--
        System.out.println(years[k++]+"t"+winners[l++]);
    }while(i>=0 || j>=0);

您将发现输出如下:

Years   Premiers
1995    January
1997    February
1998    June
1999    January
2000    March
2001    June
2002    July
2003    August
2004    September
2005    March
2006    May
2007    January
2008    March
2009    July
2010    November
2011    March
2012    June