通过 COM 访问 PowerDesigner 存储库模型



我一直试图使用COM API直接从PowerDesigner存储库中获取实时模型,但没有成功。 这是我在 VBA 中一直在尝试的内容:

Set pd = CreateObject("PowerDesigner.Application")
Set conn = pd.RepositoryConnection
conn.Open "", "", "ShhMahPW"
Set model = conn.FindChildByPath("Program/Project/Logical Models/MahLOM", PdOOM_Classes.cls_Model)
MsgBox model.ShortDescription 'This fails because model is null!

同样,我一直在Eclipse中使用Java COM桥尝试同样的事情:

Application pd = this.getApplicationHook();
//Make live connection to proxy repository
RepositoryConnection conn = new RepositoryConnection( pd.GetRepositoryConnection() );
conn.Open( "", "", ConnectionParams.PASSWORD );

BaseObject model = conn.FindChildByPath( "Program/Project/Logical Models/MahLOM", 
                   PdOOM_Classes.cls_Model );
//Null model, COMException: "Action can not be performed. result = -2147467259"
System.out.println( model.GetShortDescription() ) 

有人可以建议一种潜入存储库的好方法吗? 我已经能够确认我与存储库有连接,然后在该顶级列出子项。 我正在努力挖掘根级别以外的文件夹。 谢谢!

我知道

我要从存储库中提取的模型已经存在于我的本地工作区中。 实际上,这是对本地工作区模型的更新。 为此,可以使用UpdateFromRepository()的方法!

因此,我能做的就是获取本地PowerDesigner模型的句柄,然后在检索子项之前调用更新。 请注意从BaseObjectBaseModel的转换,以便刷新...

private BaseObject getModel(){
    Application pd = this.getApplicationHook();
    model = pd.OpenModel(this.basePath + this.modelName);
    System.out.println( "Retrieving model updates from repository...  ");
    RepositoryConnection conn = new RepositoryConnection( pd.GetRepositoryConnection() );
    conn.Open( "", "", ConnectionParams.PASSWORD);
    boolean success = new BaseModel(model).UpdateFromRepository();
    if( success )
        System.out.println( "Update successful!" );
    else
        System.out.println( "Update failed. Check PowerDesigner settings." );
    return this.model;
}

您的主要问题是搜索ChildKind应该是 Cls_RepositoryModel ,而不是PdOOM_Class.cls_Model

   option explicit
   ' assuming we're already connected
   if RepositoryConnection.Connected then
      Descent RepositoryConnection,""
   end if
   dim c
   set c = RepositoryConnection.FindChildByPath("Folder_7/ConceptualDataModel_1", Cls_RepositoryModel)
   if not c is nothing then
      output "*** found object " & c.classname
   end if
sub Descent(obj,ofs)
   output ofs & obj.name & " - " & obj.ObjectType & " - " & obj.ClassName
   if obj.ObjectType = "RepositoryModel" then exit sub
   if obj.PermanentID = 3 then exit sub ' to save time, don't enter Library
   if not obj.HasCollection("ChildObjects") then exit sub
   dim c
   for each c in obj.ChildObjects
      Descent c,ofs & "   "
   next
end sub

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