android拆分zip文件并制作一个文件

Question

我想从服务器下载几个zip文件部分（file1.z01、file1.z02、file1.z 03等）

现在，在下载了所有的部分之后，我们可以通过代码将这些部分合并到一个zip中并制作一个zip文件吗？

Answer 1

您可以使用它，只需相应地更改值。。。

import android.util.Log; 
import java.io.BufferedInputStream; 
import java.io.BufferedOutputStream; 
import java.io.FileInputStream; 
import java.io.FileOutputStream; 
import java.util.zip.ZipEntry; 
import java.util.zip.ZipOutputStream; 

public class Compress { 
  private static final int BUFFER = 2048; 
  private String[] _files; 
  private String _zipFile; 
  public Compress(String[] files, String zipFile) { 
    _files = files; 
    _zipFile = zipFile; 
  } 
  public void zip() { 
    try  { 
      BufferedInputStream origin = null; 
      FileOutputStream dest = new FileOutputStream(_zipFile); 
      ZipOutputStream out = new ZipOutputStream(new BufferedOutputStream(dest)); 
      byte data[] = new byte[BUFFER]; 
      for(int i=0; i < _files.length; i++) { 
        Log.v("Compress", "Adding: " + _files[i]); 
        FileInputStream fi = new FileInputStream(_files[i]); 
        origin = new BufferedInputStream(fi, BUFFER); 
        ZipEntry entry = new ZipEntry(_files[i].substring(_files[i].lastIndexOf("/") + 1)); 
        out.putNextEntry(entry); 
        int count; 
        while ((count = origin.read(data, 0, BUFFER)) != -1) { 
          out.write(data, 0, count); 
        } 
        origin.close(); 
      } 
      out.close(); 
    } catch(Exception e) { 
      e.printStackTrace(); 
    } 
  } 
}

Answer 2

Zip4j有一种方便的方法来合并拆分的zip文件。

ZipFile.mergeSplitFiles(File outputZipFile)

将所有拆分的zip文件合并为一个用outputZipFile 指定的zip文件

假设您已经拆分了zip文件：ZipFileName.z01、ZipFileNamez02、ZipFileName.z03……下面的ZipFileName.zip代码将它们合并到MergedZipFile.zip

import java.io.File;
import net.lingala.zip4j.core.ZipFile;
import net.lingala.zip4j.exception.ZipException;
public class MergeZipFile {
    public static void main(String[] args) {
        try {
            ZipFile zipFile = new ZipFile("ZipFileName.zip");
            zipFile.mergeSplitFiles(new File("MergedZipFile.zip"));
        } catch (ZipException e) {
            e.printStackTrace();
        }
    }
}