uitapgesturerEncognizer返回0的位置.x值

Question

我正在为UIView的子类添加UITapGestureRecognizer。我想获得TAP活动的位置。这是我的自定义初始方法：

- (void)setup
{
    [self setUserInteractionEnabled:YES];
    UITapGestureRecognizer *singleFingerTap = [[UITapGestureRecognizer alloc] 
        initWithTarget:self 
        action:@selector(handleSingleTap:)];
    [self addGestureRecognizer:singleFingerTap];
    ...
}

这是我的单fingertap方法：

- (void)handleSingleTap:(UITapGestureRecognizer *)recognizer 
{
    CGPoint location = [recognizer locationInView:[recognizer.view superview]];
    CGFloat x = location.x;
    NSLog(@"testing = %f", (double)x);
}

这是我在不同位置进行多个水龙头的输出：

2012-10-24 22:49:53.077 TicTacToe[15561:f803] testing = 0.000000
2012-10-24 22:49:53.971 TicTacToe[15561:f803] testing = 0.000000
2012-10-24 22:49:54.671 TicTacToe[15561:f803] testing = 0.000000

很明显，我的SinglefingerTap方法被调用，但是该位置一直在说X坐标的位置为0。我是一名Objective-C Newbie，所以这可能是一个新手错误。

Answer 1

这就是我修复的方式：

- (void)handleSingleTap:(UITapGestureRecognizer *)recognizer 
{
    CGPoint location = [recognizer locationInView:[recognizer.view self]];
    CGFloat x = location.x;
    NSLog(@"testing = %f", (double)x);
}

我需要添加自我的自我