我有一些顶级组件(RegisrationPage
)与状态,它传递状态/道具转储底层组件(InputField
, Dropdown
, Datepicker
)。底层组件通过回调来改变RegistrationPage
的状态。
问题: puerendermixin不工作,因为我必须绑定传递给底层组件的state-change-callback。
问题:
如何使PureRenderMixin
以最优雅的方式工作?
让我们用代码来解释一下:
InputBlock:
const React = require('react'),
PureRenderMixin = require('react-addons-pure-render-mixin');
module.exports = React.createClass({
mixins: [PureRenderMixin],
propTypes: {
input: React.PropTypes.string,
onChange: React.PropTypes.func
},
render() {
//PROBLEM - is re-rendered each time , since onChange callback each time is an different object due bind method call
}
});
RegistrationPage:
RegistrationPage = React.createClass({
/**
* Since all state is held by `RegistrationPage` and bottom-level components are dump,
* I do _onFieldChange.bind - _onFieldChange should know which field should be changed
*/
render() {
return CreateFragment({
email: <InputBlock
input={this.state.email}
onChange={this._onFieldChange.bind(self, 'email')}/>,
firstName: <InputBlock
input={this.state.firstName}
onChange={this._onFieldChange.bind(self, 'firstName')}/>,
.........
});
},
_onFieldChange(key, event) {
//Save registered progress to store and re-render the component
AppActionCreators.saveRegisterProgress(this.state);
}
})
我的解决方法:只是传递inputFieldName
作为额外的属性,并在底层组件内做绑定。
问题是.bind()
每次调用它都会返回一个新函数。为了避免这种情况,应该在呈现之外创建函数。例如:
RegistrationPage = React.createClass({
render() {
return CreateFragment({
email: <InputBlock
input={this.state.email}
onChange={this._onEmailChange}/>,
firstName: <InputBlock
input={this.state.firstName}
onChange={this._onFirstNameChange}/>,
.........
});
},
_onFieldChange(key, event) {
//Save registered progress to store and re-render the component
AppActionCreators.saveRegisterProgress(this.state);
}
_onEmailChange() {
this._onFieldChange('email')
}
_onFirstNameChange() {
this._onFieldChange('firstName')
}
})