打字稿重命名数组中的键而不进行硬编码?

Question

我有两个数组。 1 个带有标题列表，另一个带有与这些标题匹配的名称列表。

titleList
0: "CEO"
1: "CIO"
2: "CFO"
3: "CTO"
names
0: null
1: null
2: "James Dean"
3: null
0: "Paula Dean"
1: null
2: null
3: null

如何将密钥重命名为 CIO、CTO 等的名称，使其看起来像这样

CEO: "Paula Dean"
CIO: null
CFO: null
CTO: null
CEO: null
CIO: null
CFO: "James Dean"
CTO: null

我试过了

const t = resources['titles'];
const rows = resources['names'];   
const map = rows;   
const filteredList: any[] = [];
const MAP = skills;
for (let i = 1; i < rows.length; i++) {
const object = rows[i];
for (const key in object) {       
if (MAP[key] !== null) {        
object[MAP[key]] = object[key];
}
delete object[key];        
}
filteredList.push(object);
}
return filteredList;
}

Answer 1

我猜测了您的数据结构是什么样子的，但这里有代码来创建一个对象，其中包含与rows中的值匹配的适当键titles;我以为你想要打字稿是因为你的typescript标签。

const resources = {
titles: [ "CEO", "CIO", "CFO", "CTO"],
names: [null, null, "James Dean", null]
};
const titles = resources['titles'];
const rows = resources['names'];   
const map: { [key: string]: string | null } = {};
titles.forEach((item, index) => map[item!] = rows[index]);

map现在应该是类似于以下内容的对象：

{
CEO: null,
CIO: null,
CFO: "James Dean",
CTO: null
}

Answer 2

使用 foreach，您可以执行以下操作：

const titles: string[] = [ "CEO", "CIO", "CFO", "CTO"];
const names: (string|null)[] =  [null, null, "James Dean", null];
const result: any = {};
titles.forEach((title: string, i: number) => {
result[title] = names[i];
});
console.log(result);

或者您也可以像这样使用reduce：

const titles: string[] = [ "CEO", "CIO", "CFO", "CTO"];
const names: (string|null)[] =  [null, null, "James Dean", null];
const result = titles.reduce((objToReturn: any, title: string, i) => {
objToReturn[title] = names[i];
return objToReturn;
}, {});
console.log(result);

希望这对:)有所帮助