我正在尝试将一组数据分类为 2 个单独的列表,全职和兼职。但它似乎不起作用。有人可以指出我哪里弄错了吗?
data = [(['Andrew'], ['FullTime'], [38]),
(['Fred'], ['PartTime'], [24]),
(['Chris'], ['FullTime'], [38])]
def sort(var1, datadump):
positionlist = []
for b in range(0, len(datadump)):
temp2 = datadump[b][1]
if (temp2 == var1):
positionlist.append(datadump[b])
return (positionlist)
FullTimeList = sort("FullTime", data)
PartTimeList = sort("PartTime", data)
print(FullTimeList)
print(PartTimeList)
这是通过改变
if (temp2 == var1):
自
if (temp2[0] == var1):
这是因为每个元组中的元素是包含字符串的列表,而不是字符串本身。
这个问题也可以使用两个列表推导来解决:
FullTimeList = [x for x in data if x[1][0] == 'FullTime']
PartTimeList = [x for x in data if x[1][0] == 'PartTime']
不是答案:只是一个建议。 了解如何使用 python 调试器。
python -m pdb <pythonscript.py>
在这种情况下,在第 9 行设置断点
b 9
运行程序
c
当它中断时,查看 temp2
p temp2
它告诉你
['FullTime']
查看 var1
p var1
它告诉你
'FullTime'
还有你的问题。
如果你用描述性名称命名变量和函数,你会得到更好的理解:
data = [(['Andrew'], ['FullTime'], [38]),
(['Fred'], ['PartTime'], [24]),
(['Chris'], ['FullTime'], [38])]
def filter_records(value, records):
result = []
for i in range(len(records)): # i and j are usual variable names for indices (b is not)
record = records[i]
name, work, hours = record # give names to the parts
if work[0] == value: # work[0] since the values are lists (no need for parenthesis)
result.append(record)
return result # no need for parenthesis
FullTimeList = filter_records("FullTime", data)
PartTimeList = filter_records("PartTime", data)
模式:
for i in range(len(records)):
record = records[i]
是 Python 中的一种反模式 - 这意味着有更好的编写方法:
for record in records:
...