电视马拉松问题：运行时警告：从未等待过协程'send_message'

Question

请帮我解决代码中的错误：

from telethon import TelegramClient, sync, events
#Ids
api_id = 99999
api_hash = 'secret_word'
client = TelegramClient('secret_chat', api_id, api_hash)
@client.on(events.NewMessage(chats=('user1')))
async def normal_handler(event):
s_user_id=event.message.to_dict()['from_id']
if s_user_id != 99999999:
client.send_message('user3', 'Test')

@client.on(events.NewMessage(chats=('user2')))
async def normal_handler(event):
s_user_id=event.message.to_dict()['from_id']
if s_user_id != 99999999:
client.send_message('user3', 'Test')
client.start()
client.run_until_disconnected()

当用户 1 或用户 2 向我发送消息时，我的程序中出现错误：

运行时警告：协程"send_message"从未等待
client.send_message("user3"，"测试"(

Answer 1

使用下一个代码修复：

from telethon import TelegramClient, sync, events
#Ids
api_id = 99999
api_hash = 'secret_word'
client = TelegramClient('secret_chat', api_id, api_hash)
@client.on(events.NewMessage(chats=('user1')))
async def normal_handler(event):
s_user_id=event.message.to_dict()['from_id']
await client.send_message('user3', 'Test')
if s_user_id != 99999999:
client.send_message('user3', 'Test')

@client.on(events.NewMessage(chats=('user2')))
async def normal_handler(event):
s_user_id=event.message.to_dict()['from_id']
await client.send_message('user3', 'Test')
if s_user_id != 99999999:
client.send_message('user3', 'Test')
client.start()
client.run_until_disconnected()

但是现在，client.send_message工作甚至s_user_id= 99999999。 不知何故，如果s_user_id ！= 99999999，代码会忽略：