移动 2D 数组中的某些元素

Question

给定一个二维数组。如果[i][0] == name，如何将其移动到数组的最后一个元素？

String[][] array2d = [ [continents, name, Asia, Europe, Africa, Australia, South America, North America, Antartica],
[profession, Teacher, Doctor, Lawyer],
[brand, Apple, Samsung],
[name, Lisa, Peter, Sam, Jake],
[profession, Engineer, Professor, Dentist, Driver],
[sex, value, Male, Female],
[exp, value, 1, 2, 3, 4, 6]]

我想要的输出是

[ [continents, name, Asia, Europe, Africa, Australia, South America, North America, Antartica],
[profession, Teacher, Doctor, Lawyer],
[brand, Apple, Samsung],
[profession, Engineer, Professor, Dentist, Driver],
[sex, value, Male, Female],
[exp, value, 1, 2, 3, 4, 6],
[name, Lisa, Peter, Sam, Jake]
]

以下是代码

String[][] newArray =new String[array2d.length][];
for (int i = 0; i < newArray.length; ++i) {
newArray[i] = new String[array2d[i].length];
for (int j = 0; j < newArray[i].length; ++j) {
if (array2d[i][0] != "name") {
newArray[i][j] = array2d[i][j];
}
}
}

但是，输出是

[[continents, name, Asia, Europe, Africa, Australia, South America, North America, Antartica],
[profession, Teacher, Doctor, Lawyer],
[brand, Apple, Samsung],
[null, null, null, null, null],
[profession, Engineer, Professor, Dentist, Driver],
[sex, value, Male, Female],
[exp, value, 1, 2, 3, 4, 6]]

谢谢！

Answer 1

第一个备份最后一个元素(它是一个一维数组(，将数组的最后一个元素深度复制到临时变量作为var(，然后将您选择的(它是一个一维数组(元素复制到数组的最后一个元素。最后复制将最后一个元素备份到数组的所选元素中。 这是伪代码。

if(array[i][0] == name){  
var = deepCopy(array[last]
array[last] = deepCopy(array[i])
array[i] = var
}

此链接是关于深拷贝的

Answer 2

你可以这样尝试...您只需要重新排列数组引用

package testProgram;
import java.util.Scanner;
public class TwoDArray {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String[][] array = new String[7][];
array[0] = new String[] { "continents", "Asia", "Europe", "Africa", "Australia", "South America",
"North America" };
array[1] = new String[] { "profession", "teacher", "doctor", "lawyer" };
array[2] = new String[] { "brand", "apple", "samsung" };
array[3] = new String[] { "name", "lisa", "peter", "sam", "jack" };
array[4] = new String[] { "profession", "engineer", "Professor", "Dentist", "Driver" };
array[5] = new String[] { "sex", "value", "male", "female" };
array[6] = new String[] { "exp", "value", "1", "2", "3", "4" };
int index = sc.nextInt();
//shuffling array references
String[] tempReference = array[index - 1];
for (int i = index - 1; i < array.length - 1; i++) {
array[i] = array[i + 1];
}
array[array.length - 1] = tempReference;
for (String[] tempArray : array) {
for (String s : tempArray) {
System.out.print(s + " ");
}
System.out.println();
}
}
}

Answer 3

public static void main(String[] args) {
//Initialize
String[][] arr = new String[][]{
new String[]{"continents", "abc"},
new String[]{"name", "test"},
new String[]{"something", "test something"},
};
int indexOfNameArray = -1;
//Continuous swap logic
for (int i = 0; i < arr.length; i++) {
if (indexOfNameArray > -1 && indexOfNameArray < arr.length - 1) {
String[] temp = arr[i];
arr[i] = arr[i - 1];
arr[i - 1] = temp;
indexOfNameArray = i;
} else if (arr[i][0].equals("name")) {
indexOfNameArray = i;
}
}
//To display output
for (int i = 0; i < arr.length; i++) {
for (int j = 0; j < arr[i].length; j++) {
System.out.print(arr[i][j] + ", ");
}
System.out.println();
}
}