Android 工作室，等待一行代码完成，然后再开始下一步

Question

初学者问题...

我有以下 4 行代码。

第三行询问用户(带语音(他/她是否确定某个动作。

然后，第四行调用一个名为speechYesNo(包含在下面(的方法来侦听用户的响应。

问题是在 txtSpeech.speak 行(第 3 行(完成说话之前调用了 speechYesNo 方法，它记录了"你确定..."的语音台词以及用户的响应。

例如，如果用户响应"是"，则 speechYesNo 方法的结果将类似于..."您确定要添加 xxxxx 是的吗"。

我只希望结果是"是"。

有没有办法在调用 speechYesNo(( 方法之前强制第三行 (txtSpeech.speak( 完成？

谢谢

String strCommonName = myUtil.getCommonName(strFinalResult);
String strToSpeak = "Are you sure you would like to add " + strCommonName;
txtSpeech.speak(strToSpeak, TextToSpeech.QUEUE_FLUSH, null);
speechYesNo();

这是演讲是不是((方法

public void speechYesNo() {
Intent intent = new Intent(RecognizerIntent.ACTION_RECOGNIZE_SPEECH);
intent.putExtra(RecognizerIntent.EXTRA_LANGUAGE_MODEL, RecognizerIntent.LANGUAGE_MODEL_FREE_FORM);
intent.putExtra(RecognizerIntent.EXTRA_LANGUAGE, Locale.getDefault());
if(intent.resolveActivity(getPackageManager()) != null) {
startActivityForResult(intent, 9);
} else {
Toast.makeText(context, "Your device does not support Speech Input.", Toast.LENGTH_LONG).show();
}
}

这是活动结果...

@Override
protected void onActivityResult(int requestCode, int resultCode, @Nullable Intent data) {
super.onActivityResult(requestCode, resultCode, data);
switch (requestCode) {
case 10:
if(resultCode == RESULT_OK && data != null) {
ArrayList<String> result = data.getStringArrayListExtra(RecognizerIntent.EXTRA_RESULTS);
String strResult = result.get(0);
Double dblStringComparison = 0.000;
String strFinalResult = "Unknown";
for(int intCount = 0; intCount <= arrAnimals.size()-1; intCount++) {
String strVal1 = strResult;
String strVal2 = myUtil.getCommonName(arrAnimals.get(intCount));
Double dblTemp = myUtil.similarity(strVal1, strVal2 );
if(dblTemp > dblStringComparison){
dblStringComparison = dblTemp;
strFinalResult = arrAnimals.get(intCount);
}
}

atvAnimalName.setText(strFinalResult);
String strCommonName = myUtil.getCommonName(strFinalResult);
String strToSpeak = "Are you sure you would like to add " + strCommonName;
txtSpeech.speak(strToSpeak, TextToSpeech.QUEUE_FLUSH, null);
speechYesNo();
}
break;
case 9:
if(resultCode == RESULT_OK && data != null) {
ArrayList<String> result2 = data.getStringArrayListExtra(RecognizerIntent.EXTRA_RESULTS);
String strYesNo0 = result2.get(0);
Toast.makeText(context, strYesNo0, Toast.LENGTH_LONG).show();
}
break;
}
}

这是完整的脚本

当用户单击图像时，将触发 openSpeechMode 方法，并将记录用户的语音选择。

完成此操作后，我希望应用程序询问用户他/她是否确定他/她的选择。

如果用户回答"是"，那么我将做更多的工作。

如上所述的问题是语音记录器正在记录"您确定"问题以及"是"响应。

public void openSpeechMode(View view) {
Intent intent = new Intent(RecognizerIntent.ACTION_RECOGNIZE_SPEECH);
intent.putExtra(RecognizerIntent.EXTRA_LANGUAGE_MODEL, RecognizerIntent.LANGUAGE_MODEL_FREE_FORM);
intent.putExtra(RecognizerIntent.EXTRA_LANGUAGE, Locale.getDefault());
if(intent.resolveActivity(getPackageManager()) != null) {
startActivityForResult(intent, 10);
} else {
Toast.makeText(context, "Your device does not support Speech Input.", Toast.LENGTH_LONG).show();
}
}

public void speechYesNo() {
Intent intent = new Intent(RecognizerIntent.ACTION_RECOGNIZE_SPEECH);
intent.putExtra(RecognizerIntent.EXTRA_LANGUAGE_MODEL, RecognizerIntent.LANGUAGE_MODEL_FREE_FORM);
intent.putExtra(RecognizerIntent.EXTRA_LANGUAGE, Locale.getDefault());
if(intent.resolveActivity(getPackageManager()) != null) {
startActivityForResult(intent, 9);
} else {
Toast.makeText(context, "Your device does not support Speech Input.", Toast.LENGTH_LONG).show();
}
}

@Override
protected void onActivityResult(int requestCode, int resultCode, @Nullable Intent data) {
super.onActivityResult(requestCode, resultCode, data);
switch (requestCode) {
case 10:
if(resultCode == RESULT_OK && data != null) {
ArrayList<String> result = data.getStringArrayListExtra(RecognizerIntent.EXTRA_RESULTS);
String strResult = result.get(0);
Double dblStringComparison = 0.000;
String strFinalResult = "Unknown";
for(int intCount = 0; intCount <= arrAnimals.size()-1; intCount++) {
String strVal1 = strResult;
String strVal2 = myUtil.getCommonName(arrAnimals.get(intCount));
Double dblTemp = myUtil.similarity(strVal1, strVal2 );
if(dblTemp > dblStringComparison){
dblStringComparison = dblTemp;
strFinalResult = arrAnimals.get(intCount);
}
}

atvAnimalName.setText(strFinalResult);
String strCommonName = myUtil.getCommonName(strFinalResult);
String strToSpeak = "Are you sure you would like to add " + strCommonName;
txtSpeech.speak(strToSpeak, TextToSpeech.QUEUE_FLUSH, null);
//                    speechYesNo();
}
break;
case 9:
if(resultCode == RESULT_OK && data != null) {
ArrayList<String> result2 = data.getStringArrayListExtra(RecognizerIntent.EXTRA_RESULTS);
String strYesNo0 = result2.get(0);
Toast.makeText(context, strYesNo0, Toast.LENGTH_LONG).show();
}
break;
}
}

Answer 1

问题

speechYesNo问题是在txtSpeech.speak

溶液

txtSpeech似乎是TextToSpeech类。 因此，您应该使用 UtteranceProgressListener 来解决您的问题。

尝试以下代码。

txtSpeech.setOnUtteranceProgressListener(new UtteranceProgressListener() {
@Override
public void onStart(String utteranceId) {
}
@Override
public void onDone(String utteranceId) {
speechYesNo();
}
@Override
public void onError(String utteranceId) {
}
});
txtSpeech.speak(strToSpeak, TextToSpeech.QUEUE_FLUSH, null);